(a) Does the entropy of the surroundings increase for spontaneous processes? (b) In a particular spontaneous process the entropy of the system decreases. What can you conclude about the sign and magnitude of $\Delta S_{\text {surr }} ?$ (c) During a certain reversible process, the surroundings undergo an entropy change, \(\Delta S_{\text {surt }}=-78 \mathrm{~J} / \mathrm{K} .\) What is the entropy change of the system for this process?

Short Answer

Expert verified
(a) For spontaneous processes, the overall entropy change in the universe must be positive. If the entropy of the system decreases but the entropy of the surroundings increases by an even larger amount, the total entropy change will still be positive, and the process will be spontaneous. (b) Since the given process is spontaneous and the entropy of the system decreases, the entropy change of the surroundings (∆S_surr) must be positive and greater in magnitude than the decrease in entropy of the system. (c) In a reversible process, the total entropy change in the universe is zero. Given ∆S_surr = -78 J/K, we can conclude that the entropy change of the system, ∆S_sys, is positive and equal in magnitude: \(\Delta S_{\text {sys}} = 78 \mathrm{~J} / \mathrm{K}\).

Step by step solution

01

Part (a) - Entropy of Surroundings in Spontaneous Processes

For spontaneous processes, the overall entropy change in the universe must be positive, meaning the total entropy should increase for the process to be spontaneous. This consists of both the entropy change in the system (∆S_sys) and the entropy change in the surroundings (∆S_surr). Thus, if the entropy of the system increases and the surroundings remain unchanged, the total entropy change will be positive and the process will be spontaneous. Similarly, if the entropy of the system decreases but the entropy of the surroundings increases by an even larger amount, then the total entropy change will still be positive, and the process will be spontaneous.
02

Part (b) - Sign and Magnitude of ∆S_surr

Since the given process is spontaneous and the entropy of the system decreases, the entropy change of the surroundings (∆S_surr) must be positive and greater in magnitude than the decrease in entropy of the system. By doing so, the overall entropy change in the universe (∆S_univ = ∆S_sys + ∆S_surr) will be positive, and the process will be spontaneous.
03

Part (c) - Entropy change of the system during a reversible process

In a reversible process, the total entropy change in the universe is zero. This means that the entropy change in the system (∆S_sys) is equal in magnitude and opposite in sign to the entropy change in the surroundings (∆S_surr). Since ∆S_surr is given as -78 J/K, we can conclude that the entropy change of the system, ∆S_sys, is positive and equal in magnitude: \[\Delta S_{\text {sys}} = 78 \mathrm{~J} / \mathrm{K}\]

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Using \(S^{\circ}\) values from Appendix \(\mathrm{C}\), calculate $\Delta S^{\circ}$ values for the following reactions. In each case, account for the sign of \(\Delta S\). (a) $\mathrm{NH}_{4} \mathrm{Cl}(s) \longrightarrow \mathrm{NH}_{4}^{+}(a q)+\mathrm{Cl}^{-}(a q)$ (b) $\mathrm{CH}_{3} \mathrm{OH}(g) \longrightarrow \mathrm{CO}(g)+2 \mathrm{H}_{2}(g)$ (c) $\mathrm{CH}_{4}(g)+2 \mathrm{O}_{2}(g) \longrightarrow \mathrm{CO}_{2}(g)+2 \mathrm{H}_{2} \mathrm{O}(g)$ (d) $\mathrm{CH}_{4}(g)+2 \mathrm{O}_{2}(g) \longrightarrow \mathrm{CO}_{2}(g)+2 \mathrm{H}_{2} \mathrm{O}(l)$

Indicate whether \(\Delta G\) increases, decreases, or stays the same for each of the following reactions as the partial pressure of \(\mathrm{O}_{2}\) is increased: (a) \(\mathrm{HgO}(s) \longrightarrow \mathrm{Hg}(l)+\mathrm{O}_{2}(g)\) (b) $2 \mathrm{SO}_{2}(g)+\mathrm{O}_{2}(g) \longrightarrow 2 \mathrm{SO}_{3}(g)$ (c)

The conversion of natural gas, which is mostly methane, into products that contain two or more carbon atoms, such as ethane $\left(\mathrm{C}_{2} \mathrm{H}_{6}\right)$, is a very important industrial chemical process. In principle, methane can be converted into ethane and hydrogen: $$ 2 \mathrm{CH}_{4}(g) \longrightarrow \mathrm{C}_{2} \mathrm{H}_{6}(g)+\mathrm{H}_{2}(g) $$ In practice, this reaction is carried out in the presence of oxygen: $$ 2 \mathrm{CH}_{4}(g)+\frac{1}{2} \mathrm{O}_{2}(g) \longrightarrow \mathrm{C}_{2} \mathrm{H}_{6}(g)+\mathrm{H}_{2} \mathrm{O}(g) $$ (a) Using the data in Appendix \(C\), calculate \(K\) for these reactions at \(25^{\circ} \mathrm{C}\) and \(500^{\circ} \mathrm{C}\). (b) Is the difference in \(\Delta G^{\circ}\) for the two reactions due primarily to the enthalpy term \((\Delta H)\) or the entropy term \((-T \Delta S)\) ? (c) Explain how the preceding reactions are an example of driving a nonspontaneous reaction, as discussed in the "Chemistry and Life" box in Section 19.7. (d) The reaction of \(\mathrm{CH}_{4}\) and \(\mathrm{O}_{2}\) to form \(\mathrm{C}_{2} \mathrm{H}_{6}\) and \(\mathrm{H}_{2} \mathrm{O}\) must be carried out carefully to avoid a competing reaction. What is the most likely competing reaction?

Indicate whether each statement is true or false. (a) \(\Delta S\) depends on whether the process is reversible or irreversible. \((\mathbf{b})\) If a system undergoes an irreversible change, the entropy of the universe increases. (c) Only if the change in entropy of the system is exactly matched by an equal and opposite change in the entropy of the surroundings, the system undergoes a reversible process. (d) If the entropy change of the system is zero, the system undergoes a reversible process.

The normal boiling point of the element mercury (Hg) is $356.7{ }^{\circ} \mathrm{C},\( and its molar enthalpy of vaporization is \)\Delta H_{\text {vap }}=59.11 \mathrm{~kJ} / \mathrm{mol} .$ (a) When Hg boils at its nor- mal boiling point, does its entropy increase or decrease? (b) Calculate the value of \(\Delta S\) when \(2.00 \mathrm{~mol}\) of \(\mathrm{Hg}\) is vaporized at \(356.7^{\circ} \mathrm{C}\).

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free