Bromine has two naturally occurring isotopes, bromine- 79 (atomic mass \(=78.9183 \mathrm{u} ; \quad\) abundance \(=50.69 \%)\) a \(\mathrm{nd}\) bromine-81 \(\quad\) (atomic mass \(=80.9163 \mathrm{u} ;\) abundance \(=\) $49.31 \%) .$ Calculate the atomic weight of bromine.

Short Answer

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The atomic weight of bromine can be calculated using the weighted average of its naturally occurring isotopes, bromine-79 and bromine-81. By multiplying the atomic masses of each isotope by their respective abundances in decimal form and then adding these contributions, we find that the atomic weight of bromine is approximately 79.8910 u.

Step by step solution

01

Determine the atomic mass of each isotope with its abundance.

First, we need to find the product of the atomic mass for bromine-79 and bromine-81 by their respective abundances provided in percentage. For bromine-79: Atomic mass = 78.9183 u Abundance = 50.69 % For bromine-81: Atomic mass = 80.9163 u Abundance = 49.31 %
02

Convert percentage abundance into decimal form.

To simplify calculations, we need to convert percentage abundance into decimal form. To do this, divide the percentage abundance by 100. For bromine-79: Abundance = 50.69 % / 100 = 0.5069 For bromine-81: Abundance = 49.31 % / 100 = 0.4931
03

Compute the contribution of each isotope's atomic mass to the atomic weight of bromine.

Multiply the atomic mass of each isotope by their corresponding abundance in decimal form. For bromine-79: Contribution = 78.9183 u * 0.5069 = 39.9943 u For bromine-81: Contribution = 80.9163 u * 0.4931 = 39.8967 u
04

Calculate the atomic weight of bromine.

Add the contributions of both isotopes to get the atomic weight of bromine. Atomic weight = Contribution of bromine-79 + Contribution of bromine-81 Atomic weight = 39.9943 u + 39.8967 u Atomic weight = 79.8910 u The atomic weight of bromine is approximately 79.8910 u.

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