How many of the indicated atoms are represented by each chemical formula: (a) carbon atoms in \(\mathrm{C}_{4} \mathrm{H}_{9} \mathrm{COOCH}_{3}\),(b) oxygen atoms in \(\mathrm{Ca}\left(\mathrm{ClO}_{3}\right)_{2}\), (c) hydrogen atoms in \(\left(\mathrm{NH}_{4}\right)_{2} \mathrm{HPO}_{4} ?\)

Short Answer

Expert verified
There are 6 carbon atoms in \(\mathrm{C}_{4} \mathrm{H}_{9} \mathrm{COOCH}_{3}\), 6 oxygen atoms in \(\mathrm{Ca}\left(\mathrm{ClO}_{3}\right)_{2}\), and 9 hydrogen atoms in \(\left(\mathrm{NH}_{4}\right)_{2} \mathrm{HPO}_{4}\).

Step by step solution

01

(a) Carbon atoms in \(\mathrm{C}_{4} \mathrm{H}_{9} \mathrm{COOCH}_{3}\)

In the chemical formula \(\mathrm{C}_{4} \mathrm{H}_{9} \mathrm{COOCH}_{3}\), there are three parts to look for carbon atoms. 1. The \(\mathrm{C}_{4}\) part has 4 carbon atoms. 2. The \(\mathrm{COO}\) part has 1 carbon atom. 3. The \(\mathrm{CH}_{3}\) part has 1 carbon atom. To find the total number of carbon atoms, add the number of carbon atoms from each part: \(4 + 1 + 1 = 6\). Therefore, there are 6 carbon atoms in \(\mathrm{C}_{4} \mathrm{H}_{9} \mathrm{COOCH}_{3}\).
02

(b) Oxygen atoms in \(\mathrm{Ca}\left(\mathrm{ClO}_{3}\right)_{2}\)

In the chemical formula \(\mathrm{Ca}\left(\mathrm{ClO}_{3}\right)_{2}\), the part containing oxygen atoms is \(\left(\mathrm{ClO}_{3}\right)_{2}\). The subscript 3 indicates that there are 3 oxygen atoms in each \(\mathrm{ClO}_{3}\) unit. Since there is a coefficient of 2 for the \(\left(\mathrm{ClO}_{3}\right)_{2}\) part, there are two \(\mathrm{ClO}_{3}\) units in the formula. To find the total number of oxygen atoms, multiply the number of oxygen atoms in each unit by the number of units: \(3 \times 2 = 6\). Therefore, there are 6 oxygen atoms in \(\mathrm{Ca}\left(\mathrm{ClO}_{3}\right)_{2}\).
03

(c) Hydrogen atoms in \(\left(\mathrm{NH}_{4}\right)_{2} \mathrm{HPO}_{4}\)

In the chemical formula \(\left(\mathrm{NH}_{4}\right)_{2} \mathrm{HPO}_{4}\), there are two parts to look for hydrogen atoms. 1. The \(\left(\mathrm{NH}_{4}\right)_{2}\) part has 4 hydrogen atoms in each \(\mathrm{NH}_{4}\) unit, and there are 2 units because of the subscript 2. Multiply the number of hydrogen atoms in each unit by the number of units: \(4 \times 2 = 8\). 2. The \(\mathrm{HPO}_{4}\) part has 1 hydrogen atom. To find the total number of hydrogen atoms, add the number of hydrogen atoms from each part: \(8 + 1 = 9\). Therefore, there are 9 hydrogen atoms in \(\left(\mathrm{NH}_{4}\right)_{2} \mathrm{HPO}_{4}\).

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