Name the following ionic compounds: $(\mathbf{a}) \mathrm{KCN},(\mathbf{b}) \mathrm{NaBrO}_{2},\( (c) \)\mathrm{Sr}(\mathrm{OH})_{2}$ (d) CoTe, (e) \(\mathrm{Fe}_{2}\left(\mathrm{CO}_{3}\right)_{3},\) (f) \(\mathrm{Cr}\left(\mathrm{NO}_{3}\right)_{3}\) (h) $\mathrm{NaH}_{2} \mathrm{PO}_{4}\( (g) \)\left(\mathrm{NH}_{4}\right)_{2} \mathrm{SO}_{3},$ (i) $\mathrm{KMnO}_{4},(\mathbf{j}) \mathrm{Ag}_{2} \mathrm{Cr}_{2} \mathrm{O}_{7}$.

The first step in naming an ionic compound is identifying the metal (cation) and non-metal (anion) along with any present polyatomic ions.

Name the cation (metal ion) and the anion (non-metal or polyatomic ion). For metals with only one charge, simply use the metal's name. For metals with multiple charges, use Roman numerals to indicate the charge. For non-metals, change their ending to "-ide." For polyatomic ions, use their designated name.

After naming both cation and anion, combine their names to give the complete name of the ionic compound. Now, let's apply these steps to each compound: a) KCN Step 1: Cation: K (Potassium), Anion: CN (Cyanide) Step 2: K (Potassium), CN (Cyanide) Step 3: Potassium Cyanide b) NaBrO₂ Step 1: Cation: Na (Sodium), Anion: BrO₂ (Bromite) Step 2: Na (Sodium), BrO₂ (Bromite) Step 3: Sodium Bromite c) Sr(OH)₂ Step 1: Cation: Sr (Strontium), Anion: OH (Hydroxide) Step 2: Sr (Strontium), OH (Hydroxide) Step 3: Strontium Hydroxide d) CoTe Step 1: Cation: Co (Cobalt), Anion: Te (Tellurium) Step 2: Co (Cobalt), Te (Telluride) Step 3: Cobalt Telluride e) Fe₂(CO₃)₃ Step 1: Cation: Fe (Iron), Anion: CO₃ (Carbonate) Step 2: Fe (Iron), CO₃ (Carbonate) - Iron has a multiple possible charges, so we need to determine the charge using the chemical formula. For this compound, we see that there is a balanced charge: 2(Fe³⁺)+3(CO₃²⁻). Therefore, Iron must have a charge of +3. Step 3: Iron(III) Carbonate f) Cr(NO₃)₃ Step 1: Cation: Cr (Chromium), Anion: NO₃ (Nitrate) Step 2: Cr (Chromium), NO₃ (Nitrate) - Since there are 3 nitrates and chromium is in a 3+ state, using the chemical formula, we have Cr³⁺+3(NO₃⁻) Step 3: Chromium(III) Nitrate g) NaH₂PO₄ Step 1: Cation: Na (Sodium), Anion: H₂PO₄ (Dihydrogen phosphate) Step 2: Na (Sodium), H₂PO₄ (Dihydrogen phosphate) Step 3: Sodium Dihydrogen Phosphate h) (NH₄)₂SO₃ Step 1: Cation: NH₄ (Ammonium), Anion: SO₃ (Sulfite) Step 2: NH₄ (Ammonium), SO₃ (Sulfite) Step 3: Ammonium Sulfite i) KMnO₄ Step 1: Cation: K (Potassium), Anion: MnO₄ (Permanganate) Step 2: K (Potassium), MnO₄ (Permanganate) Step 3: Potassium Permanganate j) Ag₂Cr₂O₇ Step 1: Cation: Ag (Silver), Anion: Cr₂O₇ (Dichromate) Step 2: Ag (Silver), Cr₂O₇ (Dichromate) - Silver has only one charge, which is +1. Step 3: Silver(I) Dichromate