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Chapter 2: Problem 74

Give the chemical formula for each of the following ionic compounds: (a) sodium phosphate, (b) zinc nitrate, (c) barium bromate, \((\mathbf{d})\) iron(II) perchlorate, \((\mathbf{e})\) cobalt(II) hydrogen carbonate, (f) chromium(III) acetate, \((\mathbf{g})\) potassium dichromate.

Short Answer

Expert verified
The chemical formulas for the given ionic compounds are: (a) \(\ce{Na3PO4}\), (b) \(\ce{Zn(NO3)2}\), (c) \(\ce{Ba(BrO3)2}\), (d) \(\ce{Fe(ClO4)2}\), (e) \(\ce{Co(HCO3)2}\), (f) \(\ce{Cr(CH3COO)3}\), and (g) \(\ce{K2Cr2O7}\).

Step by step solution

01

(a) Sodium Phosphate

The ions in this compound are sodium (Na+) and phosphate (PO4^3-). To balance the charges, we need 3 sodium ions for each phosphate ion. The chemical formula is: \[ \ce{Na3PO4} \]
02

(b) Zinc Nitrate

The ions in this compound are zinc (Zn^2+) and nitrate (NO3^-). To balance the charges, we need 2 nitrate ions for each zinc ion. The chemical formula is: \[ \ce{Zn(NO3)2} \]
03

(c) Barium Bromate

The ions in this compound are barium (Ba^2+) and bromate (BrO3^-). To balance the charges, we need 2 bromate ions for each barium ion. The chemical formula is: \[ \ce{Ba(BrO3)2} \]
04

(d) Iron(II) Perchlorate

Iron(II) means that iron has a +2 charge (Fe^2+), and the ion in this compound is perchlorate (ClO4^-). To balance the charges, we need 2 perchlorate ions for each iron(II) ion. The chemical formula is: \[ \ce{Fe(ClO4)2} \]
05

(e) Cobalt(II) Hydrogen Carbonate

Cobalt(II) means that cobalt has a +2 charge (Co^2+), and the ion in this compound is hydrogen carbonate (HCO3^-). To balance the charges, we need 2 hydrogen carbonate ions for each cobalt(II) ion. The chemical formula is: \[ \ce{Co(HCO3)2} \]
06

(f) Chromium(III) Acetate

Chromium(III) means that chromium has a +3 charge (Cr^3+), and the ion in this compound is acetate (CH3COO^-). To balance the charges, we need 3 acetate ions for each chromium(III) ion. The chemical formula is: \[ \ce{Cr(CH3COO)3} \]
07

(g) Potassium Dichromate

The ions in this compound are potassium (K+) and dichromate (Cr2O7^2-). To balance the charges, we need 2 potassium ions for each dichromate ion. The chemical formula is: \[ \ce{K2Cr2O7} \]

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Most popular questions from this chapter

Millikan determined the charge on the electron by studying the static charges on oil drops falling in an electric field (Figure 2.5\()\). A student carried out this experiment using several oil drops for her measurements and calculated the charges on the drops. She obtained the following data: $$ \begin{array}{lc} \hline \text { Droplet } & \text { Calculated Charge (C) } \\ \hline \text { A } & 1.60 \times 10^{-19} \\ \text {B } & 3.15 \times 10^{-19} \\ \text {C } & 4.81 \times 10^{-19} \\ \text {D } & 6.31 \times 10^{-19} \\ \hline \end{array} $$ (a) What is the significance of the fact that the droplets carried different charges? (b) What conclusion can the student draw from these data regarding the charge of the electron? (c) What value (and to how many significant figures) should she report for the electronic charge?

Each of the following isotopes is used in medicine. Indicate the number of protons and neutrons in each isotope: (a) samarium-153, (b) lutetium-177, (c) bismuth-213, (d) molybdenum-99, (e) lead-212, (f) caesium-131.

Predict the chemical formulas of the compounds formed by the following pairs of ions: (a) \(\mathrm{Cr}^{3+}\) and \(\mathrm{CN}^{-}\), (b) \(\mathrm{Mn}^{2+}\) and \(\mathrm{ClO}_{4}^{-}\), (c) \(\mathrm{Na}^{+}\) and $\mathrm{Cr}_{2} \mathrm{O}_{7}^{2-}\(, (d) \)\mathrm{Cd}^{2+}\( and \)\mathrm{CO}_{3}^{2-}$, (e) \(\mathrm{Ti}^{4+}\) and \(\mathrm{O}^{2-}\).

Consider the following organic substances: ethylethanoate, ethylmethylether, hexanol, and propanone. (a) Which of these molecules contains three carbons? (b) Which of these molecules contain a \(\mathrm{C}=\) O group?

Identify the element represented by each of the following symbols and give the number of protons and neutrons in each: $(\mathbf{a})_{5}^{11} X(\mathbf{b})_{33}^{75} X(\mathbf{c})_{36}^{86} X(\mathbf{d}) \frac{67}{30} X$.
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