For each of the following balanced oxidation-reduction reactions, (i) identify the oxidation numbers for all the elements in the reactants and products and (ii) state the total number of electrons transferred in each reaction. (a) \(\mathrm{H}_{2}(g)+\mathrm{F}_{2}(g) \longrightarrow 2 \mathrm{HF}(g)\) (b) $2 \mathrm{Fe}^{2+}(a q)+\mathrm{H}_{2} \mathrm{O}_{2}(a q)+2 \mathrm{H}^{+}(a q) \longrightarrow 2 \mathrm{Fe}^{3+}(a q)+\mathrm{H}_{2} \mathrm{O}(l)$ (c) $\mathrm{CH}_{4}(g)+2 \mathrm{O}_{2}(g) \longrightarrow \mathrm{CO}_{2}(g)+2 \mathrm{H}_{2} \mathrm{O}(l)$

Short Answer

Expert verified
(a) In the reaction \(\mathrm{H}_{2}(g)+\mathrm{F}_{2}(g) \longrightarrow 2 \mathrm{HF}(g)\), Hydrogen goes from 0 to +1, and Fluorine goes from 0 to -1. The total number of electrons transferred is 2. (b) In the reaction \(2 \mathrm{Fe}^{2+}(a q)+\mathrm{H}_{2} \mathrm{O}_{2}(a q)+2 \mathrm{H}^{+}(a q) \longrightarrow 2 \mathrm{Fe}^{3+}(a q)+\mathrm{H}_{2} \mathrm{O}(l)\), Iron goes from +2 to +3, and Oxygen goes from -1 in \(\mathrm{H}_{2} \mathrm{O}_{2}\) to -2 in \(\mathrm{H}_{2} \mathrm{O}\). The total number of electrons transferred is 2. (c) In the reaction $\mathrm{CH}_{4}(g)+2 \mathrm{O}_{2}(g) \longrightarrow \mathrm{CO}_{2}(g)+2 \mathrm{H}_{2} \mathrm{O}(l)$, Carbon goes from -4 to +4, and Oxygen goes from 0 to -2. The total number of electrons transferred is 8.

Step by step solution

01

Assign oxidation numbers

Using the oxidation number rules, assign oxidation numbers to each element in the reactants and the products: - In \(\mathrm{H}_{2}(g)\), Hydrogen has an oxidation number of 0 since it's in its elemental form. - In \(\mathrm{F}_{2}(g)\), Fluorine has an oxidation number of 0 since it's in its elemental form. - In \(\mathrm{HF}(g)\), Hydrogen has an oxidation number of +1, and Fluorine has an oxidation number of -1.
02

Determine electrons transferred

To determine the number of electrons transferred in the reaction, find the change in oxidation numbers for the elements involved in the redox process: - Hydrogen: 0 (in \(\mathrm{H}_{2}\)) to +1 (in \(\mathrm{HF}\)), a change of +1 - Fluorine: 0 (in \(\mathrm{F}_{2}\)) to -1 (in \(\mathrm{HF}\)), a change of -1 Since there are 2 moles of \(\mathrm{HF}\) produced, two electrons are transferred in total. (b) $2 \mathrm{Fe}^{2+}(a q)+\mathrm{H}_{2} \mathrm{O}_{2}(a q)+2 \mathrm{H}^{+}(a q) \longrightarrow 2 \mathrm{Fe}^{3+}(a q)+\mathrm{H}_{2} \mathrm{O}(l)$
03

Assign oxidation numbers

Assign oxidation numbers to each element in the reactants and the products: - In \(\mathrm{Fe}^{2+}\), Iron has an oxidation number of +2. - In \(\mathrm{H}_{2} \mathrm{O}_{2}\), Hydrogen has an oxidation number of +1, and Oxygen has an oxidation number of -1. - In \(\mathrm{H}^{+}\), Hydrogen has an oxidation number of +1. - In \(\mathrm{Fe}^{3+}\), Iron has an oxidation number of +3. - In \(\mathrm{H}_{2} \mathrm{O}\), Hydrogen has an oxidation number of +1, and Oxygen has an oxidation number of -2.
04

Determine electrons transferred

To determine the number of electrons transferred in the reaction, find the change in oxidation numbers for the elements involved in the redox process: - Iron: +2 (in \(\mathrm{Fe}^{2+}\)) to +3 (in \(\mathrm{Fe}^{3+}\)), a change of +1 - Oxygen: -1 (in \(\mathrm{H}_{2} \mathrm{O}_{2}\)) to -2 (in \(\mathrm{H}_{2} \mathrm{O}\)), a change of -1 Since there are 2 moles of \(\mathrm{Fe}^{2+}\) transformed to \(\mathrm{Fe}^{3+}\), and 1 mole of \(\mathrm{H}_{2} \mathrm{O}_{2}\) transformed to \(\mathrm{H}_{2} \mathrm{O}\), two electrons are transferred in total. (c) $\mathrm{CH}_{4}(g)+2 \mathrm{O}_{2}(g) \longrightarrow \mathrm{CO}_{2}(g)+2 \mathrm{H}_{2} \mathrm{O}(l)$
05

Assign oxidation numbers

Assign oxidation numbers to each element in the reactants and the products: - In \(\mathrm{CH}_{4}\), Carbon has an oxidation number of -4, and Hydrogen has an oxidation number of +1. - In \(\mathrm{O}_{2}(g)\), Oxygen has an oxidation number of 0 since it's in its elemental form. - In \(\mathrm{CO}_{2}\), Carbon has an oxidation number of +4, and Oxygen has an oxidation number of -2. - In \(\mathrm{H}_{2} \mathrm{O}\), Hydrogen has an oxidation number of +1, and Oxygen has an oxidation number of -2.
06

Determine electrons transferred

To determine the number of electrons transferred in the reaction, find the change in oxidation numbers for the elements involved in the redox process: - Carbon: -4 (in \(\mathrm{CH}_{4}\)) to +4 (in \(\mathrm{CO}_{2}\)), a change of +8 - Oxygen: 0 (in \(\mathrm{O}_{2}\)) to -2 (in \(\mathrm{H}_{2} \mathrm{O}\) and \(\mathrm{CO}_{2}\)), a change of -2 Since there are 2 moles of \(\mathrm{O}_{2}(g)\) transformed, oxygen transfers a total of 4 electrons. Hence, there is a transfer of 8 electrons in total in this reaction (4 from Carbon to Oxygen, and 4 from Hydrogen to Oxygen).

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Most popular questions from this chapter

Cytochrome, a complicated molecule that we will represent as \(\mathrm{CyFe}^{2+}\), reacts with the air we breathe to supply energy required to synthesize adenosine triphosphate (ATP). The body uses ATP as an energy source to drive other reactions (Section 19.7). At \(\mathrm{pH} 7.0\) the following reduction potentials pertain to this oxidation of \(\mathrm{CyFe}^{2+}\) $$ \begin{aligned} \mathrm{O}_{2}(g)+4 \mathrm{H}^{+}(a q)+4 \mathrm{e}^{-} & \longrightarrow 2 \mathrm{H}_{2} \mathrm{O}(l) & & E_{\mathrm{red}}^{\circ}=+0.82 \mathrm{~V} \\\ \mathrm{CyFe}^{3+}(a q)+\mathrm{e}^{-} & \longrightarrow \mathrm{CyFe}^{2+}(a q) & E_{\mathrm{red}}^{\circ} &=+0.22 \mathrm{~V} \end{aligned} $$ (a) What is \(\Delta G\) for the oxidation of \(\mathrm{CyFe}^{2+}\) by air? \((\mathbf{b})\) If the synthesis of \(1.00 \mathrm{~mol}\) of ATP from adenosine diphosphate (ADP) requires a \(\Delta G\) of \(37.7 \mathrm{~kJ},\) how many moles of ATP are synthesized per mole of \(\mathrm{O}_{2} ?\)

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Indicate whether the following balanced equations involve oxidation-reduction. If they do, identify the elements that undergo changes in oxidation number. (a) $2 \mathrm{NO}_{2}(g)+\mathrm{H}_{2} \mathrm{O}_{2}(a q) \longrightarrow 2 \mathrm{HNO}_{3}(a q)$ (b) $\mathrm{FeS}(s)+2 \mathrm{HCl}(a q) \longrightarrow \mathrm{FeCl}_{2}(a q)+\mathrm{H}_{2} \mathrm{~S}(g)$ (c) $\mathrm{Fe}(s)+2 \mathrm{HNO}_{3}(a q) \longrightarrow \mathrm{H}_{2} \mathrm{O}(l)+ 2 \mathrm{NO}_{2}(g)+\mathrm{FeO}(s)$

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