(a) What conditions must be met for a reduction potential to be a standard reduction potential? (b) What is the standard reduction potential of a standard hydrogen electrode? (c) Why is it impossible to measure the standard reduction potential of a single half-reaction?

Short Answer

Expert verified
(a) A reduction potential is considered a standard reduction potential when: 1) the temperature is 298 K (25°C), 2) the pressure is 1 atm (101.325 kPa), and 3) the concentration of each ion in the reaction is 1 M (1 mol L^-1). (b) The standard reduction potential of a standard hydrogen electrode (SHE) is defined as 0 Volts (V) under standard conditions (298 K, 1 atm, and 1 M concentration). (c) It is impossible to measure the standard reduction potential of a single half-reaction because an electrochemical cell requires two half-reactions (connected in a complete redox reaction) for a potential difference to exist and be measured. Comparing the measured potential difference between the unknown half-reaction and the SHE directly gives the standard reduction potential of the unknown half-reaction.

Step by step solution

01

a) Conditions for standard reduction potential

To be considered a standard reduction potential, a reduction potential must meet the following conditions: 1. Temperature: The measurement must be taken at a temperature of 298 K (25 degrees Celsius). 2. Pressure: The pressure must be set at 1 atmosphere (atm) or 101.325 kPa. 3. Concentration: The concentration of each ion in the reaction must be 1 M (1 mol L^-1). By keeping these conditions constant, it is possible to compare the reduction potentials of various half-reactions.
02

b) Standard reduction potential of a standard hydrogen electrode

The standard hydrogen electrode (SHE) is a common reference electrode used in electrochemistry. It consists of a platinum wire coated with a thin layer of platinum black, and it is immersed in an acidic solution (pH = 0) containing hydrogen ions (H+) with a concentration of 1 M. Hydrogen gas (H2) is continuously bubbled through the solution at a pressure of 1 atm. By definition, the SHE is assigned a standard reduction potential of 0 Volts (V) under standard conditions (298 K, 1 atm, and 1 M concentration). This value serves as a reference point for measuring and comparing the standard reduction potentials of other electrodes.
03

c) Why is it impossible to measure the standard reduction potential of a single half-reaction?

In electrochemistry, a half-reaction represents either the reduction or oxidation process in an overall redox reaction. The standard reduction potential of a half-reaction is the potential difference between the half-reaction and the SHE under standard conditions. However, it is impossible to measure the standard reduction potential of a single half-reaction because there is no flow of electrons between the half-reaction and SHE when they are isolated from each other. The flow of electrons occurs only when both half-reactions are connected to form a complete redox reaction within an electrochemical cell. To measure the standard reduction potential of a half-reaction, the half-reaction must be paired with another half-reaction to form a complete redox reaction. By connecting the two half-reactions to form an electrochemical cell, a potential difference can be measured between them. This potential difference represents the sum of the standard reduction potentials of the two half-reactions. Since the standard reduction potential of the SHE is defined as 0 V, comparing the measured potential difference between the unknown half-reaction and the SHE directly gives the standard reduction potential of the unknown half-reaction. Thus, it is impossible to measure the standard reduction potential of a single half-reaction because an electrochemical cell requires two half-reactions (connected in a complete redox reaction) for a potential difference to exist and be measured.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

For a spontaneous reaction $\mathrm{A}(a q)+\mathrm{B}(a q) \longrightarrow \mathrm{A}^{-}(a q)+$ \(\mathrm{B}^{+}(a q),\) answer the following questions: (a) If you made a voltaic cell out of this reaction, what halfreaction would be occurring at the cathode, and what half reaction would be occurring at the anode? (b) Which half-reaction from (a) is higher in potential energy? (c) What is the sign of \(E_{\text {cell }}^{\circ}\) ?

(a) What is meant by the term oxidation? (b) On which side of an oxidation half-reaction do the electrons appear? (c) What is meant by the term oxidant? (d) What is meant by the term oxidizing agent?

A mixture of copper and gold metals that is subjected to electrorefining contains tellurium as an impurity. The standard reduction potential between tellurium and its lowest common oxidation state, \(\mathrm{Te}^{4+}\), is $$ \mathrm{Te}^{4+}(a q)+4 \mathrm{e}^{-} \longrightarrow \mathrm{Te}(s) \quad E_{\mathrm{red}}^{\circ}=0.57 \mathrm{~V} $$ Given this information, describe the probable fate of tellurium impurities during electrorefining. Do the impurities fall to the bottom of the refining bath, unchanged, as copper is oxidized, or do they go into solution as ions? If they go into solution, do they plate out on the cathode?

Mercuric oxide dry-cell batteries are often used where a flat discharge voltage and long life are required, such as in watches and cameras. The two half-cell reactions that occur in the battery are $$ \begin{array}{l} \mathrm{HgO}(s)+\mathrm{H}_{2} \mathrm{O}(l)+2 \mathrm{e}^{-} \longrightarrow \mathrm{Hg}(l)+2 \mathrm{OH}^{-}(a q) \\ \mathrm{Zn}(s)+2 \mathrm{OH}^{-}(a q) \longrightarrow \mathrm{ZnO}(s)+\mathrm{H}_{2} \mathrm{O}(l)+2 \mathrm{e}^{-} \end{array} $$ (a) Write the overall cell reaction. (b) The value of $E_{\text {red }}^{\circ}\( for the cathode reaction is \)+0.098 \mathrm{~V}$. The overall cell potential is \(+1.35 \mathrm{~V}\). Assuming that both half-cells operate under standard conditions, what is the standard reduction potential for the anode reaction? (c) Why is the potential of the anode reaction different than would be expected if the reaction occurred in an acidic medium?

In a Li-ion battery the composition of the cathode is \(\mathrm{LiCoO}_{2}\) when completely discharged. On charging, approximately \(50 \%\) of the \(\mathrm{Li}^{+}\) ions can be extracted from the cathode and transported to the graphite anode where they intercalate between the layers. (a) What is the composition of the cathode when the battery is fully charged? (b) If the \(\mathrm{LiCoO}_{2}\) cathode has a mass of \(10 \mathrm{~g}\) (when fully discharged), how many coulombs of electricity can be delivered on completely discharging a fully charged battery?

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free