The isotope \({ }_{28}^{62} \mathrm{Ni}\) has the largest binding energy per nucleon of any isotope. Calculate this value from the atomic mass of nickel-62 \((61.928345 \mathrm{u})\) and compare it with the value given for iron- 56 in Table 21.7 .

Short Answer

Expert verified
The binding energy per nucleon for nickel-62 can be calculated using the formula: \(Binding \ Energy = (Z * m_p + (A - Z) * m_n - M) * c^2\), where Z = 28, A = 62, m_p = 1.007276 u, m_n = 1.008664 u, and M = 61.928345 u. After calculating the binding energy, we can find the binding energy per nucleon by dividing it by the total number of nucleons (A). Finally, compare this value to the binding energy per nucleon for iron-56 given in Table 21.7.

Step by step solution

01

Recall the binding energy formula and the relevant constants

To calculate the binding energy, we need to use the formula: Binding Energy = (Z * m_p + (A - Z) * m_n - M) * c^2 where Z = number of protons, A = number of nucleons, m_p = mass of a proton (1.007276 u), m_n = mass of a neutron (1.008664 u), M = atomic mass of the isotope (given as 61.928345 u for nickel-62), c = speed of light (approximately 2.99792458 * 10^8 m/s, but we will only require the square of c which is c^2 = 8.98755179 * 10^16 m^2/s^2), and 1 u = 931.494 MeV/c^2.
02

Calculate the number of protons and neutrons for nickel-62

The isotope notation indicates that nickel-62 has an atomic number (Z) of 28, which means it has 28 protons. To find the number of neutrons (A - Z), we subtract the number of protons from the total number of nucleons, which is also given in the isotope notation as 62. Number of neutrons = A - Z = 62 - 28 = 34
03

Calculate the binding energy of nickel-62

Now that we have all the relevant values, we can plug them into the binding energy formula: Binding Energy = (Z * m_p + (A - Z) * m_n - M) * c^2 = (28 * 1.007276 + 34 * 1.008664 - 61.928345) * 8.98755179 * 10^16 * (931.494)
04

Calculate the binding energy per nucleon for nickel-62

To find the binding energy per nucleon, divide the binding energy by the total number of nucleons (A): Binding Energy per nucleon = Binding Energy / A
05

Compare the binding energy per nucleon of nickel-62 with that of iron-56

Refer to Table 21.7 provided for the binding energy per nucleon of iron-56. Compare the calculated binding energy per nucleon of nickel-62 with this value.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

(a) What is the function of the moderator in a nuclear reactor? (b) What substance acts as the moderator in a pressurized water generator? (c) What other substances are used as a moderator in nuclear reactor designs?

(a) Which of the following are required characteristics of an isotope to be used as a fuel in a nuclear power reactor? (i) It must emit gamma radiation. (ii) On decay, it must release two or more neutrons. (iii) It must have a half-life less than one hour. (iv) It must undergo fission upon the absorption of a neutron. (b) What is the most common fissionable isotope in a commercial nuclear power reactor?

According to current regulations, the maximum permissible dose of strontium-90 in the body of an adult is $1 \mu \mathrm{Ci}\left(1 \times 10^{-6} \mathrm{Ci}\right)\(. Using the relationship rate \)=k N$, calculate the number of atoms of strontium-90 to which this dose corresponds. To what mass of strontium-90 does this correspond? The half-life for strontium-90 is $28.8 \mathrm{yr}$

The average energy released in the fission of a single uranium- 235 nucleus is about \(3 \times 10^{-11} \mathrm{~J}\). If the conversion of this energy to electricity in a nuclear power plant is \(40 \%\) efficient, what mass of uranium- 235 undergoes fission in a year in a plant that produces 1000 megawatts? Recall that a watt is \(1 \mathrm{~J} / \mathrm{s}\).

What do these symbols stand for? (a) \({ }_{0}^{0} \gamma,(\mathbf{b}){ }_{2}^{4} \mathrm{He},\) (c) \({ }_{0}^{1} \mathrm{n} .\)

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free