Iodine-131 is a convenient radioisotope to monitor thyroid activity in humans. It is a beta emitter with a half-life of 8.02 days. The thyroid is the only gland in the body that uses iodine. A person undergoing a test of thyroid activity drinks a solution of NaI, in which only a small fraction of the iodide is radioactive. (a) Why is NaI a good choice for the source of iodine? (b) If a Geiger counter is placed near the person's thyroid (which is near the neck) right after the sodium iodide solution is taken, what will the data look like as a function of time? (c) A normal thyroid will take up about \(12 \%\) of the ingested iodide in a few hours. How long will it take for the radioactive iodide taken up and held by the thyroid to decay to \(0.01 \%\) of the original amount?

Short Answer

Expert verified
NaI is a good choice for the source of iodine in thyroid tests because it is highly soluble in water, iodine is the active component monitored in the thyroid, and sodium is chemically inert. The Geiger counter data will follow an exponential decay function as the radioactive iodine in the thyroid decreases over time. It will take approximately 51.36 days for the radioactive iodide taken up and held by the thyroid to decay to \(0.01 \%\) of the original amount.

Step by step solution

01

Part (a): Choosing NaI for the source of iodine

NaI is a good choice for the source of iodine in thyroid tests because of the following reasons: 1. NaI is highly soluble in water, making it easy to prepare in a solution that can be ingested by a person. 2. Iodine is the active component that will be monitored in the thyroid, as it is the only gland in the body that uses iodine. 3. Sodium (Na) is chemically inert in this context and does not interfere with the iodine uptake by the thyroid gland nor does it cause any harmful side effects. Thus, NaI works well for ingesting the iodine and monitoring its uptake by the thyroid gland.
02

Part (b): Geiger counter data as a function of time

After ingestion of the sodium iodide solution, the radioactive iodine (I-131) will be taken up by the thyroid gland. Right after drinking the solution, the Geiger counter will detect a higher number of radioactive iodine decays. As time passes, the amount of radioactive iodine in the thyroid will decrease due to decay and the Geiger counter will detect progressively lower counts. The data will follow an exponential decay function, which is characteristic for radioactive decay processes. Mathematically, the number of radioactive iodine decays detected by the Geiger counter can be represented by the function: \[ N(t) = N_0 e^{-\lambda t} \] Where: - \(N(t)\) is the number of radioactive iodine decays at time \(t\), - \(N_0\) is the initial number of radioactive iodine decays, - \(\lambda\) is the decay constant, - \(t\) is the time since ingesting the sodium iodide solution.
03

Part (c): Time taken for radioactive iodide to decay to \(0.01 \%\) of the original amount

To calculate the time it takes for the radioactive iodide taken up and held by the thyroid to decay to \(0.01 \%\) of the original amount, we'll use the radioactive decay formula: \[ N(t) = N_0 e^{-\lambda t} \] First, we need to find the decay constant \(\lambda\) using the half-life formula: \[ t_{1/2} = \frac{\ln{2}}{\lambda} \] Given the half-life (\(t_{1/2}\)) of Iodine-131 as 8.02 days, we can find the decay constant: \[ \lambda = \frac{\ln{2}}{8.02} \approx 0.0865 \, \text{day}^{-1} \] Now, we're given that the normal thyroid takes up about \(12\%\) of the ingested iodide. We're trying to find the time \(t\) required for the radioactive iodide to decay to \(0.01 \%\) of the original amount. Let's set up the equation: \[ 0.0001 N_0 = (0.12 N_0) e^{-0.0865 t} \] Divide both sides by \(0.12 N_0\): \[ \frac{0.0001}{0.12} = e^{-0.0865 t} \] Now, take the natural logarithm of both sides: \[ \ln{\frac{0.0001}{0.12}} = -0.0865 t \] Finally, solve for \(t\): \[ t = \frac{\ln{\frac{0.0001}{0.12}}}{-0.0865} \] \[ t \approx 51.36 \, \text{days} \] So, it will take approximately 51.36 days for the radioactive iodide taken up and held by the thyroid to decay to \(0.01 \%\) of the original amount.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

How much time is required for a \(5.00-g\) sample of \({ }^{233}\) Pa to decay to \(0.625 \mathrm{~g}\) if the half-life for the beta decay of ${ }^{233} \mathrm{~Pa}$ is 27.4 days?

In 2002 , a team of scientists from Russia and the United States reported the creation of the first atom of element 118 , which is named oganesson, and whose symbol is Og. The synthesis involved the collision of californium- 249 atoms with accelerated ions of an atom which we will denote X. In the synthesis, an oganesson-294 is formed together with three neutrons. $$ { }_{98}^{249} \mathrm{Cf}+\mathrm{X} \longrightarrow{ }_{118}^{294} \mathrm{Og}+3{ }_{0}^{1} \mathrm{n} $$ (a) What are the identities of isotopes X? (b) Isotope \(X\) is unusual in that it is very long-lived (its half-life is on the order of \(10^{19} \mathrm{yr}\) ) in spite of having an unfavorable neutron-to-proton ratio (Figure 21.1). Can you propose a reason for its unusual stability? (c) Oganesson-294 decays into livermorium-290 by alpha decay. Write a balanced equation for this.

Which statement best explains why nuclear transmutations involving neutrons are generally easier to accomplish than those involving protons or alpha particles? (a) Neutrons are not a magic number particle. (b) Neutrons do not have an electrical charge. (c) Neutrons are smaller than protons or alpha particles. (d) Neutrons are attracted to the nucleus even at long distances, whereas protons and alpha particles are repelled.

It takes 180 minutes for a 200 -mg sample of an unknown radioactive substance to decay to \(112 \mathrm{mg}\). What is the halflife of this substance?

A \(2.5-\mathrm{mL}\) sample of \(0.188 \mathrm{M}\) silver nitrate solution was mixed with \(2.5 \mathrm{~mL}\) of \(0.188 \mathrm{M}\) sodium chloride solution labeled with radioactive chlorine-36. The activity of the initial sodium chloride solution was \(2.46 \times 10^{6} \mathrm{~Bq} / \mathrm{mL}\). After the resultant precipitate was removed by filtration, the remaining filtrate was found to have an activity of 175 Bq/mL. (a) Write a balanced chemical equation for the reaction that occurred. (b) Calculate the \(K_{s p}\) for the precipitate under the conditions of the experiment.

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free