Write the chemical formula for each of the following compounds, and indicate the oxidation state of nitrogen in each: (a) dinitrogen trioxide, (b) dinitrogen pentoxide, (c) hydrogen cyanide, (d) ammonium nitrate, (e) iron(III) nitrite, \((\mathbf{f})\) nitrogen trichloride.

Short Answer

Expert verified
The chemical formulas and oxidation states of nitrogen for the given compounds are: a) \(N_2O_3\): +3 b) \(N_2O_5\): +5 c) \(HCN\): -3 d) \(NH_4NO_3\): -3 (in ammonium) and +5 (in nitrate) e) \(Fe(NO_2)_3\): +3 f) \(NCl_3\): +3

Step by step solution

01

Write the chemical formula

To write the chemical formula for each compound, we need to balance the charges of the elements involved. We'll do this for each compound listed: a) Dinitrogen trioxide: There are 2 nitrogen (N) atoms and 3 oxygen (O) atoms. Chemical formula: \(N_2O_3\) b) Dinitrogen pentoxide: There are 2 nitrogen (N) atoms and 5 oxygen (O) atoms. Chemical formula: \(N_2O_5\) c) Hydrogen cyanide: There is 1 hydrogen (H) atom, 1 carbon (C) atom, and 1 nitrogen (N) atom. Chemical formula: \(HCN\) d) Ammonium nitrate: This compound contains 1 ammonium ion (\(NH_4^+\)) and 1 nitrate ion (\(NO_3^-\)). Chemical formula: \(NH_4NO_3\) e) Iron(III) nitrite: This compound contains 1 iron (Fe) ion with a charge of +3 and 3 nitrite ions (\(NO_2^-\)) to balance the charge. Chemical formula: \(Fe(NO_2)_3\) f) Nitrogen trichloride: There is 1 nitrogen (N) atom and 3 chlorine (Cl) atoms. Chemical formula: \(NCl_3\)
02

Determine the oxidation state of nitrogen

We will apply the oxidation state rules to find the oxidation state of nitrogen in each compound: a) In \(N_2O_3\), the oxidation state of oxygen is typically -2. The overall charge of the molecule is 0, and there are two nitrogen atoms, so the combined oxidation state of the nitrogen atoms is +6 (3 x (-2) = -6). For each nitrogen atom, the oxidation state is +3. Oxidation state of N in \(N_2O_3\): +3 b) In \(N_2O_5\), the oxidation state of oxygen is typically -2. The overall charge of the molecule is 0, and there are two nitrogen atoms, so the combined oxidation state of the nitrogen atoms is +10 (5 x (-2) = -10). For each nitrogen atom, the oxidation state is +5. Oxidation state of N in \(N_2O_5\): +5 c) In \(HCN\), the oxidation state of hydrogen is typically +1, and carbon's oxidation state is +2 (since it's part of a cyanide ion). Nitrogen's oxidation state balances the charge in the cyanide ion. Oxidation state of N in \(HCN\): -3 d) In \(NH_4NO_3\), the ammonium ion (NH4+) has an oxidation state of +1 for hydrogen and -3 for nitrogen, and the nitrate ion (\(NO_3^-\)) has an oxidation state of -2 for oxygen and +5 for nitrogen. Oxidation states of N in \(NH_4NO_3\): -3 (in ammonium) and +5 (in nitrate) e) In \(Fe(NO_2)_3\), the iron ion has an oxidation state of +3, and the oxidation state of oxygen in nitrite ions is typically -2. Nitrogen balances the charge in the nitrite ion. Oxidation state of N in \(Fe(NO_2)_3\): +3 f) In \(NCl_3\), the oxidation state of chlorine is typically -1. Nitrogen balances the charge in the molecule. Oxidation state of N in \(NCl_3\): +3

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Most popular questions from this chapter

Write a balanced equation for each of the following reactions. (You may have to guess at one or more of the reaction products, but you should be able to make a reasonable guess, based on your study of this chapter.) (a) Hydrogen selenide can be prepared by reaction of an aqueous acid solution on aluminum selenide. (b) Sodium thiosulfate is used to remove excess \(\mathrm{Cl}_{2}\) from chlorine-bleached fabrics. The thiosulfate ion forms \(\mathrm{SO}_{4}^{2-}\) and elemental sulfur, while \(\mathrm{Cl}_{2}\) is reduced to \(\mathrm{Cl}^{-}\).

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