(a) The \(\mathrm{P}_{4}, \mathrm{P}_{4} \mathrm{O}_{6}\) and $\mathrm{P}_{4} \mathrm{O}_{10}$ molecules have a common structural feature of four \(\mathrm{P}\) atoms arranged in a tetrahedron (Figures 22.27 and 22.28 ). Does this mean that the bonding between the \(\mathrm{P}\) atoms is the same in all these cases? Explain. (b) Sodium trimetaphosphate $\left(\mathrm{Na}_{3} \mathrm{P}_{3} \mathrm{O}_{9}\right)$ and sodium tetrametaphosphate \(\left(\mathrm{Na}_{4} \mathrm{P}_{4} \mathrm{O}_{12}\right)\) are used as water-softening agents. They contain cyclic $\mathrm{P}_{3} \mathrm{O}_{9}^{3-}\( and \)\mathrm{P}_{4} \mathrm{O}_{12}{ }^{4-}$ ions, respectively. Propose reasonable structures for these ions.

Short Answer

Expert verified
The bonding between P atoms in P4, P4O6, and P4O10 is not the same in all cases due to the differences in their bonding with oxygen atoms. The P3O9^3- ion has a cyclic structure with three P=O double bonds and three P-O-P single bonds, while the P4O12^4- ion has a cyclic structure with four P=O double bonds and four P-O-P single bonds.

Step by step solution

01

Determine the bonding in P4, P4O6, and P4O10

In order to determine the bonding between the P atoms in each molecule, let us consider the following: 1. P4: It is a tetrahedron with four P atoms. Each P atom forms single bonds with the other three P atoms. 2. P4O6: This molecule consists of a P4 tetrahedron, with two oxygen atoms bonded to each P atom, forming P=O bonds. Each P atom still forms single bonds with the other three P atoms. 3. P4O10: In this molecule, each P atom in the P4 tetrahedron is bonded to five other atoms: three P atoms and two oxygen atoms. The bonding between P atoms becomes weaker due to the presence of double bonds with oxygen atoms. The bonding between the P atoms in P4, P4O6, and P4O10 is not the same in all cases due to the differences in the bonding with the oxygen atoms.
02

Propose structures for P3O9^3- and P4O12^4- ions

To propose reasonable structures for the cyclic P3O9^3- and P4O12^4- ions, we need to consider their bonding. 1. P3O9^3-: In this ion, we have three P atoms and nine O atoms. Each P atom can form double bonds with two O atoms (P=O), resulting in six O atoms. This leaves three O atoms, which can connect the three P atoms, forming a cyclic structure with P-O-P single bonds. Structure for P3O9^3- ion: A cyclic structure with three P=O double bonds and three P-O-P single bonds. 2. P4O12^4-: In this ion, we have four P atoms and twelve O atoms. Similar to the P3O9^3- ion, each P atom can form double bonds with two O atoms (P=O), resulting in eight O atoms. This leaves four more O atoms, which can connect the four P atoms, forming a cyclic structure with P-O-P single bonds. Structure for P4O12^4- ion: A cyclic structure with four P=O double bonds and four P-O-P single bonds.

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