Polydentate ligands can vary in the number of coordination positions they occupy. In each of the following, identify the polydentate ligand present and indicate the probable number of coordination positions it occupies: (a) \(\operatorname{Cr}(\mathrm{EDTA})^{-}\) (b) $\left[\mathrm{Ni}\left(\mathrm{C}_{2} \mathrm{O}_{4}\right)\left(\mathrm{H}_{2} \mathrm{O}\right)_{2}\right] \mathrm{Br}_{2}$ (c) $\left[\mathrm{Ru}(\mathrm{en})\left(\mathrm{NH}_{3}\right)_{4}\right] \mathrm{Cl}_{3}$ (d) \(\mathrm{K}_{2}\left[\mathrm{Fe}(\mathrm{O}\) -phen \()(\mathrm{CN})_{4}\right]\)

Short Answer

Expert verified
(a) In the complex \(\operatorname{Cr}(\mathrm{EDTA})^{-}\), the polydentate ligand is EDTA (ethylenediaminetetraacetic acid) which is a hexadentate ligand, hence it occupies six coordination positions. (b) In the complex \(\left[\mathrm{Ni}\left(\mathrm{C}_{2}\mathrm{O}_{4}\right)\left(\mathrm{H}_{2} \mathrm{O}\right)_{2}\right]\mathrm{Br}_{2}\), the polydentate ligand is oxalate (\(\mathrm{C}_{2}\mathrm{O}_{4}^{2-}\)), which is a bidentate ligand, so it occupies two coordination positions. (c) In the complex \(\left[\mathrm{Ru}(\mathrm{en})\left(\mathrm{NH}_{3}\right)_{4}\right]\mathrm{Cl}_{3}\), the polydentate ligand is ethylenediamine (en), which is a bidentate ligand, and thus it occupies two coordination positions. (d) In the complex \(\mathrm{K}_{2}\left[\mathrm{Fe}(\mathrm{O}\)-phen\((\mathrm{CN})_{4}\right]\), the polydentate ligand is O-phenanthroline (O-phen). This ligand is a bidentate ligand and therefore occupies two coordination positions.

Step by step solution

01

(a) Identify and analyze the EDTA ligand

In the given compound \(\operatorname{Cr}(\mathrm{EDTA})^{-}\), the polydentate ligand present is EDTA (ethylenediaminetetraacetic acid). The EDTA ligand possesses six donor atoms - two amine nitrogens and four carboxylate oxygens that can coordinate with the central metal ion. Therefore, EDTA is a hexadentate ligand.
02

(a) Determine the coordination positions of EDTA

As EDTA is a hexadentate ligand, it occupies six coordination positions in the complex \(\operatorname{Cr}(\mathrm{EDTA})^{-}\).
03

(b) Identify and analyze the oxalate ligand

In the given compound \(\left[\mathrm{Ni}\left(\mathrm{C}_{2} \mathrm{O}_{4}\right)\left(\mathrm{H}_{2} \mathrm{O}\right)_{2}\right] \mathrm{Br}_{2}\), the polydentate ligand present is oxalate \(\left(\mathrm{C}_{2} \mathrm{O}_{4}^{2-}\right)\). The oxalate ligand contains two donor atoms being the two carbonyl oxygens, so it is bidentate.
04

(b) Determine the coordination positions of the oxalate ligand

The oxalate ligand, as a bidentate ligand, occupies two coordination positions in the compound.
05

(c) Identify and analyze the ethylenediamine ligand

In the given compound \(\left[\mathrm{Ru}(\mathrm{en})\left(\mathrm{NH}_{3}\right)_{4}\right] \mathrm{Cl}_{3}\), the polydentate ligand present is ethylenediamine (en). The ethylenediamine ligand has two donor atoms, both being amine nitrogens, and is therefore a bidentate ligand.
06

(c) Determine the coordination positions of the ethylenediamine ligand

As a bidentate ligand, ethylenediamine occupies two coordination positions in the compound.
07

(d) Identify and analyze the O-phenanthroline ligand

In the given compound \(\mathrm{K}_{2}\left[\mathrm{Fe}(\mathrm{O}\) -phen \()(\mathrm{CN})_{4}\right]\), the polydentate ligand present is O-phenanthroline (O-phen). The O-phenanthroline ligand contains two donor atoms, being the two nitrogen atoms, so it is a bidentate ligand.
08

(d) Determine the coordination positions of the O-phenanthroline ligand

The O-phenanthroline ligand occupies two coordination positions in the complex, as it is a bidentate ligand.

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Most popular questions from this chapter

The molecule dimethylphosphinoethane $\left[\left(\mathrm{CH}_{3}\right)_{2} \mathrm{PCH}_{2} \mathrm{CH}_{2}\right.$ \(\mathrm{P}\left(\mathrm{CH}_{3}\right)_{2},\) which is abbreviated dmpe] is used as a ligand for some complexes that serve as catalysts. A complex that contains this ligand is \(\mathrm{Mo}(\mathrm{CO})_{4}(\) dmpe \()\). (a) Draw the Lewis structure for dmpe, and compare it with ethylenediamine as a coordinating ligand. (b) What is the oxidation state of Mo in \(\mathrm{Na}_{2}\left[\mathrm{Mo}(\mathrm{CN})_{2}(\mathrm{CO})_{2}(\) dmpe \()\right] ?(\mathbf{c})\) Sketch the structure of the $\left[\mathrm{Mo}(\mathrm{CN})_{2}(\mathrm{CO})_{2}(\text { dmpe })\right]^{2-}$ ion, including all the possible isomers.

How many electrons are in the valence \(d\) orbitals in these transition-metal ions? $(\mathbf{a}) \mathrm{Ru}^{3+},(\mathbf{b}) \mathrm{Pd}^{2+},(\mathbf{c}) \mathrm{Ti}^{2+},\( (d) \)\mathrm{W}^{6+}$.

Carbon monoxide is toxic because it binds more strongly to the iron in hemoglobin (Hb) than does \(\mathrm{O}_{2}\), as indicated by these approximate standard free-energy changes in blood: $$ \begin{aligned} \mathrm{Hb}+\mathrm{O}_{2} & \longrightarrow \mathrm{HbO}_{2} & \Delta G^{\circ}=-70 \mathrm{~kJ} \\ \mathrm{Hb}+\mathrm{CO} & \longrightarrow \mathrm{HbCO} & \Delta G^{\circ}=-80 \mathrm{~kJ} \end{aligned} $$ Using these data, estimate the equilibrium constant at 298 K for the equilibrium $$ \mathrm{HbO}_{2}+\mathrm{CO} \rightleftharpoons \mathrm{HbCO}+\mathrm{O}_{2} $$

(a) Sketch a diagram that shows the definition of the crystalfield splitting energy \((\Delta)\) for an octahedral crystal-field. \((\mathbf{b})\) What is the relationship between the magnitude of \(\Delta\) and the energy of the \(d-d\) transition for a \(d^{1}\) complex? (c) Calculate \(\Delta\) in $\mathrm{kJ} / \mathrm{mol}\( if a \)d^{1}\( complex has an absorption maximum at \)545 \mathrm{nm}$.

Sketch the structure of the complex in each of the following compounds and give the full compound name: (a) $c i s-\left[\operatorname{PtBr} \mathrm{Cl}\left(\mathrm{NO}_{2}\right)_{2}\right]^{2-}$ (b) $\left[\mathrm{Mn}(\mathrm{CO})_{3}\left(\mathrm{C}_{6} \mathrm{H}_{6}\right)\right]^{+}$ (c) $\left.c i s-\left[\mathrm{Cr} \mathrm{Cl}_{4}\right)\left(\mathrm{OH}_{2}\right)_{2}\right]^{-}$ (d) trans-[Co(OH)(en) \(\left._{2} \mathrm{Cl}\right]^{+}\)

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