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Chapter 23: Problem 35

Write the formula for each of the following compounds, being sure to use brackets to indicate the coordination sphere: (a) triamminetriaquachromium(III) nitrate (b) dichlorobis(ethylenediamine)platinum(II) (c) pentacarbonyliron(0) (d) ammonium diaquabis(oxalato)Co(II) (e) tris(bipyridyl)cobalt(III) sulfate

Short Answer

Expert verified
The formulas for the given compounds are: (a) \([Cr(NH₃)₃(H₂O)₃](NO₃)₃\) (b) \([PtCl₂(en)₂]²+\) (c) \([Fe(CO)₅]₀\) (d) \((NH₄)₂[Co(H₂O)₂(C₂O₄)₂]\) (e) \([Co(bipy)₃]₂(SO₄)₃\)

Step by step solution

01

Identify the central metal ion, ligands, and counter-ion

The central metal ion is chromium(III) (Cr³+), the ligands are three ammine groups (NH₃) and three aqua groups (H₂O), and the counter-ion is nitrate (NO₃⁻).
02

Write the formula for the complex

Since there are multiple ligands, we need to indicate the coordination sphere using brackets. The formula for this complex is [Cr(NH₃)₃(H₂O)₃]³+.
03

Write the formula including the counter-ion

Since the complex has a 3+ charge, and the counter-ion (NO₃⁻) has a -1 charge, we need three nitrate ions to balance the overall charge. The formula is [Cr(NH₃)₃(H₂O)₃](NO₃)₃. (b) dichlorobis(ethylenediamine)platinum(II)
04

Identify the central metal ion, ligands, and counter-ion

The central metal ion is platinum(II) (Pt²+), the ligands are two chloro groups (Cl⁻) and two ethylenediamine molecules with the abbreviated name of en (C₂H₄(NH₂)₂), and there is no counter-ion indicated.
05

Write the formula for the complex

The formula for this complex is [PtCl₂(en)₂]²+. (c) pentacarbonyliron(0)
06

Identify the central metal ion and ligands

The central metal ion is iron(0), and the ligands are five carbonyl groups (CO).
07

Write the formula for the complex

The formula for this complex is [Fe(CO)₅]₀. (d) ammonium diaquabis(oxalato)Co(II)
08

Identify the central metal ion, ligands, and counter-ion

The central metal ion is cobalt(II) (Co²+), the ligands are two aqua groups (H₂O) and two oxalato groups (C₂O₄²⁻), and the counter-ion is ammonium (NH₄⁺).
09

Write the formula for the complex

The formula for this complex is [Co(H₂O)₂(C₂O₄)₂]²-.
10

Write the formula including the counter-ion

Since the complex has a 2- charge, and the counter-ion (NH₄⁺) has a +1 charge, we need two ammonium ions to balance the overall charge. The formula is (NH₄)₂[Co(H₂O)₂(C₂O₄)₂]. (e) tris(bipyridyl)cobalt(III) sulfate
11

Identify the central metal ion, ligands, and counter-ion

The central metal ion is cobalt(III) (Co³+), the ligands are three bipyridyl molecules with the abbreviated name of bipy (C₁₀H₈N₂), and the counter-ion is sulfate (SO₄²⁻).
12

Write the formula for the complex

The formula for this complex is [Co(bipy)₃]³+.
13

Write the formula including the counter-ion

Since the complex has a 3+ charge, and the counter-ion (SO₄²⁻) has a -2 charge, we need two cobalt complexes and three sulfate ions to balance the overall charge. The formula is [Co(bipy)₃]₂(SO₄)₃.

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Most popular questions from this chapter

For a given metal ion and set of ligands, is the crystal-field splitting energy larger for a tetrahedral or an octahedral geometry?

Identify each of the following coordination complexes as either diamagnetic or paramagnetic: (a) \(\left.\left[\mathrm{ZnBr}_{4}\right)\right]^{2-}\) (b) \(\left[\mathrm{Mn}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{3+}\) (c) \(\mathrm{OsO}_{4}\) (d) \(\left[\mathrm{PtCl}_{4}\right]^{2-}\)

When Alfred Werner was developing the field of coordination chemistry, it was argued by some that the optical activity he observed in the chiral complexes he had prepared was due to the presence of carbon atoms in the molecule. To disprove this argument, Werner synthesized a chiral complex of cobalt that had no carbon atoms in it, and he was able to resolve it into its enantiomers. Design a cobalt(III) complex that would be chiral if it could be synthesized and that contains no carbon atoms. (It may not be possible to synthesize the complex you design, but we will not worry about that for now.)

(a) If a complex absorbs light at \(610 \mathrm{nm},\) what color would you expect the complex to be? (b) What is the energy in joules of a photon with a wavelength of \(610 \mathrm{nm}\) ? (c) What is the energy of this absorption in \(\mathrm{kJ} / \mathrm{mol} ?\)

An iron complex formed from a solution containing hydrochloric acid and bipyridine is purified and analyzed. It contains $9.38 \% \mathrm{Fe}, 60.53 \%\( carbon, \)4.06 \%\( hydrogen, and \)14.12 \%$ nitrogen by mass. The remainder of the compound is chlorine. An aqueous solution of the complex has about the same electrical conductivity as an equimolar solution of \(\mathrm{K}_{2}\left[\mathrm{CuCl}_{4}\right] .\) Write the formula of the compound, using brackets to denote the iron and its coordination sphere.
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