The complexes \(\left[\mathrm{CrBr}_{6}\right]^{3-}\) and \(\left[\mathrm{Cr}\left(\mathrm{NH}_{3}\right)_{6}\right]^{3+}\) are both known. (a) Draw the \(d\) -orbital energy-level diagram for octahedral \(\mathrm{Cr}(\mathrm{III})\) complexes. (b) What gives rise to the colors of these complexes? (c) Which of the two complexes would you expect to absorb light of higher energy?

Short Answer

Expert verified
The d-orbital energy-level diagram for octahedral Cr(III) complexes shows three spin-up electrons in the lower-energy t₂g orbitals and empty e_g orbitals. The colors of these complexes arise from electronic transitions between the d-orbitals when light is absorbed. Comparing the ligand-field splitting energies for both complexes, we find that [Cr(NH₃)₆]³⁺ absorbs light of higher energy due to a larger energy gap between the t₂g and e_g orbitals, as NH₃ causes a larger splitting than Br⁻ according to the spectrochemical series.

Step by step solution

01

(a) d-orbital energy-level diagram for octahedral Cr(III) complexes

To draw the d-orbital energy-level diagram for octahedral Cr(III) complexes, we must first know the electron configuration of Cr(III). Chromium has an atomic number of 24, and its ground state electron configuration is [Ar] 3d^5 4s^1. In the Cr(III) state, it loses 3 electrons, resulting in the following electron configuration: [Ar] 3d^3. In an octahedral complex, the d-orbitals split into two sets due to the crystal field: the t₂g set (dxy, dyz, dxz) and the e_g set (dz^2, dx^2-y^2). The t₂g orbitals are lower in energy than the e_g orbitals. The Cr(III) ion has 3 electrons to distribute among the d-orbitals. These electrons will fill the t₂g orbitals first, following Hund's rule. The resulting d-orbital energy-level diagram is as follows: (1) t₂g: ↑↑↑ (three spin-up electrons) (2) e_g : (empty)
02

(b) Cause of the colors of these complexes

The colors of these complexes arise from the electronic transitions between the d-orbitals. When light is absorbed, an electron from a lower energy d-orbital (t₂g) is promoted to a higher energy d-orbital (e_g). The energy difference between these orbitals (∆E) corresponds to the energy of the absorbed photon and depends on the ligands surrounding the metal ion. Since visible light covers a range of energies (and hence colors), the absorbed light's energy (color) will determine the color of the complex as perceived by the human eye. The complementary color of the absorbed light will be observed as the color of the complex.
03

(c) Comparing the energy of absorbed light for both complexes

To determine which of the two complexes would absorb light of higher energy, we must compare the ligand-field splitting energies in both cases. Different ligands cause different degrees of splitting, which is summarized in the spectrochemical series, a list of ligands ordered by their ability to split d-orbitals: I^- < Br^- < Cl^- < F^- < OH^- < H_2O < NH_3 < en < NO_2^- < CN^- In the given complexes, the Cr ion is coordinated to Br^- in the first complex and NH_3 in the second complex. According to the spectrochemical series, NH_3 causes a larger splitting than Br^-. A larger splitting means that the energy gap between the t₂g and e_g orbitals will be greater in the [Cr(NH₃)₆]³⁺ complex compared to the [CrBr₆]³⁻ complex. Therefore, the [Cr(NH₃)₆]³⁺ complex would absorb light of higher energy, as the electronic transitions in this complex require a higher energy to promote an electron from the t₂g orbitals to the e_g orbitals.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The coordination complex \(\left[\mathrm{Cr}(\mathrm{CO})_{6}\right]\) forms colorless, diamagnetic crystals that melt at \(90^{\circ} \mathrm{C}\). (a) What is the oxidation number of chromium in this compound? (b) Given that \(\left[\mathrm{Cr}(\mathrm{CO})_{6}\right]\) is diamagnetic, what is the electron configuration of chromium in this compound? (c) Given that \(\left[\mathrm{Cr}(\mathrm{CO})_{6}\right]\) is colorless, would you expect \(\mathrm{CO}\) to be a weak-field or strong-field ligand? (d) Write the name for \(\left[\mathrm{Cr}(\mathrm{CO})_{6}\right]\) using the nomenclature rules for coordination compounds.

Draw the structure for $\mathrm{Pt}\left(\mathrm{C}_{2} \mathrm{O}_{4}\right)\left(\mathrm{NH}_{3}\right)_{2}$ and use it to answer the following questions: (a) What is the coordination number for platinum in this complex? (b) What is the coordination geometry? (c) What is the oxidation state of the platinum? (d) How many unpaired electrons are there? [Sections 23.2 and 23.6\(]\)

Write names for the following coordination compounds: (a) \(\mathrm{Na}_{3}\left[\mathrm{Fe}(\mathrm{CN})_{5} \mathrm{NO}\right]\) (b) \(\left[\mathrm{CoO}\left(\mathrm{NH}_{3}\right)_{5}\right] \mathrm{Br}\) (c) \(\mathrm{Na}_{2}\left[\mathrm{NiBr}_{4}\right]\) (d) $\left[\mathrm{Rh}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]\left[\mathrm{Ag}(\mathrm{CN})_{2}\right]_{3}$

Identify each of the following coordination complexes as either diamagnetic or paramagnetic: (a) \(\left[\operatorname{CoBr}\left(\mathrm{NH}_{3}\right)_{5}\right]^{2+}\) (b) \(\left[\mathrm{W}(\mathrm{CN})_{6}\right]^{3-}\) (c) \(\left[\mathrm{VF}_{6}\right]^{3-}\) (d) \(\left[\mathrm{Rh}(\mathrm{o}-\mathrm{phen})_{3}\right]^{3+}\)

For each of the following metals, write the electronic configuration of the atom and its \(2+\) ion: $(\mathbf{a}) \mathrm{Mn},(\mathbf{b}) \mathrm{Ru},(\mathbf{c}) \mathrm{Rh} .$ Draw the crystal-field energy-level diagram for the \(d\) orbitals of an octahedral complex, and show the placement of the \(d\) electrons for each \(2+\) ion, assuming a strong-field complex. How many unpaired electrons are there in each case?

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free