Log out Go to App
Go to App

Learning Materials

Features

Discover

Chapter 24: Problem 24

Give the molecular formula of a hydrocarbon containing six carbon atoms that is (a) a cyclic alkane, (b) a cyclic alkene, \((\mathbf{c})\) a linear alkyne, \((\mathbf{d})\) an aromatic hydrocarbon.

Short Answer

Expert verified
The molecular formulas for hydrocarbons containing six carbon atoms are: (a) cyclic alkane: \(C_6 H_{12}\), (b) cyclic alkene: \(C_6 H_{10}\), (c) linear alkyne: \(C_6 H_{10}\), and (d) aromatic hydrocarbon: \(C_6 H_6\).

Step by step solution

01

(a) Cyclic Alkane

For a cyclic alkane, the general molecular formula is \(C_n H_{2n}\). In this case, since there are six carbon atoms (\(n = 6\)), we can plug that into the formula to find the formula for this hydrocarbon: \[C_6 H_{2(6)} = C_6 H_{12}\] So, the molecular formula for a cyclic alkane containing six carbon atoms is \(C_6 H_{12}\).
02

(b) Cyclic Alkene

For a cyclic alkene, the general molecular formula is \(C_n H_{2n-2}\). Using six carbon atoms (\(n = 6\)), we can find the formula for this hydrocarbon: \[C_6 H_{2(6) - 2} = C_6 H_{10}\] So, the molecular formula for a cyclic alkene containing six carbon atoms is \(C_6 H_{10}\).
03

(c) Linear Alkyne

For a linear alkyne, the general molecular formula is \(C_n H_{2n-2}\). As in the previous cases, we'll use six carbon atoms (\(n = 6\)) to find the formula for this hydrocarbon: \[C_6 H_{2(6) - 2} = C_6 H_{10}\] So, the molecular formula for a linear alkyne containing six carbon atoms is \(C_6 H_{10}\).
04

(d) Aromatic Hydrocarbon

For an aromatic hydrocarbon with six carbon atoms, the common example is benzene. The molecular formula for benzene is \(C_6 H_6\). So, the molecular formula for an aromatic hydrocarbon containing six carbon atoms is \(C_6 H_6\). In conclusion, the molecular formulas for hydrocarbons containing six carbon atoms are: (a) cyclic alkane: \(C_6 H_{12}\), (b) cyclic alkene: \(C_6 H_{10}\), (c) linear alkyne: \(C_6 H_{10}\), and (d) aromatic hydrocarbon: \(C_6 H_6\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Start your free trial

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Indicate whether each of the following molecules is capable of geometrical isomerism. For those that are, draw the structures: (a) 2 -methylpropene, (b) 1,3-diiodobenzene, (c) 1,2-dichloropent-1-ene, (d) 3-methyl-1-butyne.

Indicate whether each statement is true or false: (a) In the alpha helical structure of proteins, ion-dipole and dipole-dipole interactions occur between the carbonyl groups of the protein backbone and polar side chains of the protein. (b) Only hydrogen bonding is involved in forming the tertiary structure of a protein.

Write a chemical equation for the formation of threonylaspartic acid from the constituent amino acids, assuming that the reaction is made possible by enzymatic catalysis.

What structural features help us identify a compound as (a) an alkane, \((\mathbf{b})\) a cycloalkane, \((\mathbf{c})\) an alkene, \((\mathbf{d})\) an alkyne, (e) a saturated hydrocarbon, (f) an aromatic hydrocarbon?

Write the condensed structural formulas for two alkenes and one alkyne that all have the molecular formula \(\mathrm{C}_{6} \mathrm{H}_{10}\).
See all solutions

Recommended explanations on Chemistry Textbooks

Ionic and Molecular Compounds

Read Explanation

Organic Chemistry

Read Explanation

Kinetics

Read Explanation

Chemical Reactions

Read Explanation

Chemical Analysis

Read Explanation

Making Measurements

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free