Log out Go to App
Go to App

Learning Materials

Features

Discover

Chapter 24: Problem 52

Write a balanced chemical equation using condensed structural formulas for \((\mathbf{a})\) the formation of butyl propionate from the appropriate acid and alcohol, \((\mathbf{b})\) the saponification (base hydrolysis) of methyl benzoate.

Short Answer

Expert verified
(a) Formation of butyl propionate: \(CH_3CH_2COOH + CH_3CH_2CH_2CH_2OH \rightarrow CH_3CH_2CH_2CH_2O_2CCH_2CH_2CH_3 + H_2O\) (b) Saponification of methyl benzoate: \(C_6H_5COOCH_3 + NaOH \rightarrow C_6H_5COONa + CH_3OH\)

Step by step solution

01

(a) Identifying the reactants for butyl propionate formation

To form butyl propionate, we need to combine an appropriate acid and alcohol. Butyl propionate has the condensed structural formula \(CH_3CH_2CH_2CH_2O_2CCH_2CH_2CH_3\). This ester is derived from propanoic acid (propionic acid) \((CH_3CH_2COOH)\) and butanol (butyl alcohol) \((CH_3CH_2CH_2CH_2OH)\).
02

(a) Writing the balanced chemical equation for butyl propionate formation

Now that we have identified the reactants, we can write the balanced chemical equation for the formation of butyl propionate. Propanoic Acid + Butanol → Butyl Propionate + Water In condensed structural formulas: \(CH_3CH_2COOH + CH_3CH_2CH_2CH_2OH \rightarrow CH_3CH_2CH_2CH_2O_2CCH_2CH_2CH_3 + H_2O\)
03

(b) Writing the balanced chemical equation for saponification of methyl benzoate

For the saponification (base hydrolysis) reaction of methyl benzoate, we need to carry out the hydrolysis reaction in the presence of a strong base such as sodium hydroxide (NaOH). Methyl benzoate has the condensed structural formula \(C_6H_5COOCH_3\). Methyl Benzoate + Sodium Hydroxide → Sodium Benzoate + Methanol In condensed structural formulas: \(C_6H_5COOCH_3 + NaOH \rightarrow C_6H_5COONa + CH_3OH\)

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Start your free trial

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Draw the condensed structures of the compounds formed from (a) butanoic acid and methanol, (b) benzoic acid and 2 -propanol, \((\mathbf{c})\) propanoic acid and dimethylamine. Name the compound in each case.

Adenine and guanine are members of a class of molecules known as purines; they have two rings in their structure. Thymine and cytosine, on the other hand, are pyrimidines, and have only one ring in their structure. Predict which have larger dispersion forces in aqueous solution, the purines or the pyrimidines.

(a) What is the empirical formula of starch? (b) What is the monomer that forms the basis of the starch polymer? (c) What bond connects the monomer units in starch: amide, acid, ether, ester, or alcohol?

(a) What is the empirical formula of cellulose? (b) What is the monomer that forms the basis of the cellulose polymer? (c) What bond connects the monomer units in cellulose: amide, acid, ether, ester, or alcohol?

Write a balanced chemical equation using condensed structural formulas for the saponification (base hydrolysis) of (a) methyl propionate, \((\mathbf{b})\) phenyl acetate.
See all solutions

Recommended explanations on Chemistry Textbooks

Chemistry Branches

Read Explanation

Chemical Analysis

Read Explanation

Kinetics

Read Explanation

Organic Chemistry

Read Explanation

Ionic and Molecular Compounds

Read Explanation

Making Measurements

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free