Log out Go to App
Go to App

Learning Materials

Features

Discover

Chapter 24: Problem 56

Write the condensed structural formula for each of the following compounds: (a) 2-ethyl-1-hexanol, (b) methyl phenyl ketone, \((\mathbf{c})\) para- bromobenzoic acid, (d) butyl ethyl ether, \((\mathbf{e}) N, N\) -dimethylbenzamide.

Short Answer

Expert verified
The condensed structural formulas for the given compounds are as follows: (a) \(CH_3CH(OH)CH(CH_3)CH_2CH_2CH_3\), (b) \(C_6H_5COCH_3\), (c) \(C_6H_4BrCOOH\), (d) \(C_4H_9OCH_2CH_3\), (e) \(C_6H_5CON(CH_3)_2\).

Step by step solution

01

Break down the name into its parts

The name 2-ethyl-1-hexanol tells us that there is a 6-carbon chain (hexane), with an alcohol group in the first carbon and an ethyl group in the second carbon. This should give a molecule with the following condensed structural formula: \(CH_3CH(OH)CH(CH_3)CH_2CH_2CH_3\). 2. methyl phenyl ketone
02

Break down the name into its parts

The name methyl phenyl ketone tells us that there is a ketone group formed between a methyl (CH3) and a phenyl (C6H5) group. This should give a molecule with the following condensed structural formula: \(C_6H_5COCH_3\). 3. para-bromobenzoic acid
03

Break down the name into its parts

The name para-bromobenzoic acid tells us that there is a benzoic acid (C6H5COOH) group with a bromine atom in the para position (opposite to the carboxyl group). This should give a molecule with the following condensed structural formula: \(C_6H_4BrCOOH\). 4. butyl ethyl ether
04

Break down the name into its parts

The name butyl ethyl ether tells us that there is an ether linkage between a butyl group (C4H9) and an ethyl group (C2H5). This should give a molecule with the following condensed structural formula: \(C_4H_9OCH_2CH_3\). 5. N, N-dimethylbenzamide
05

Break down the name into its parts

The name N, N-dimethylbenzamide tells us that there is a benzene ring with an amide group (CONH2) substituted in it, and the nitrogen atom of the amide group is attached to two methyl groups. This should give a molecule with the following condensed structural formula: \(C_6H_5CON(CH_3)_2\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Start your free trial

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Which statement best explains the chemical differences between DNA and RNA? (a) DNA has two different sugars in its sugar-phosphate backbone, but RNA only has one. (b) Thymine is one of the DNA bases, whereas RNA's corresponding base is thymine minus a methyl group. (c) The RNA sugar-phosphate backbone contains fewer oxygen atoms than DNA's backbone. (d) DNA forms double helices but RNA cannot.

Draw the condensed structural formulas for two different molecules with the formula \(\mathrm{C}_{3} \mathrm{H}_{4} \mathrm{O} .\)

Draw the two possible heterodimeric dipeptides formed by condensation reactions between glycine and alanine.

From examination of the molecular models i-v, choose the substance that \((\mathbf{a})\) can be hydrolyzed to form a solution containing glucose, \((\mathbf{b})\) is capable of forming a zwitterion, (c) is one of the four bases present in DNA, (d) reacts with an acid to form an ester, \((\mathbf{e})\) is a lipid. [Sections \(24.6-24.10]\)

Draw all the possible noncyclic structural isomers of $\mathrm{C}_{5} \mathrm{H}_{10}$ Name each compound.
See all solutions

Recommended explanations on Chemistry Textbooks

Organic Chemistry

Read Explanation

Physical Chemistry

Read Explanation

Chemistry Branches

Read Explanation

The Earths Atmosphere

Read Explanation

Kinetics

Read Explanation

Chemical Analysis

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free