Predict the ideal values for the bond angles about each carbon atom in the following molecule. Indicate the hybridization of orbitals for each carbon. $$ \mathrm{CH}_{2} \mathrm{CHCOOCH}_{3} $$

To figure out the molecular geometry around each carbon atom, count the number of atoms directly bonded to the carbon and any lone pairs on the carbon atom. 1. The first carbon(CH2): This carbon atom is connected to two hydrogen atoms and the second carbon atom. Thus, it has three regions of electron density. 2. The second carbon (CH): This carbon is attached to one hydrogen atom, the first carbon, and the third carbon (C). It also has three regions of electron density. 3. The third carbon (C): This carbon is connected to the second carbon (CH), the oxygen (O), and another oxygen (O) atom linked to the CH3 group. It has three regions of electron density. 4. The fourth carbon (CH3): This carbon is attached to the oxygen atom through a single bond and three hydrogen atoms. It has four regions of electron density.

Based on the molecular geometry identified in step 1, we can determine the hybridization of orbitals for each carbon: 1. The first carbon (CH2) has three regions of electron density, which corresponds to sp2 hybridization. 2. The second carbon (CH) also has three regions of electron density, indicating sp2 hybridization. 3. The third carbon (C) has three regions of electron density, corresponding to sp2 hybridization. 4. The fourth carbon (CH3) has four regions of electron density, which corresponds to sp3 hybridization.

With the hybridization of each carbon atom determined, we can now predict the ideal bond angles: 1. The first carbon (CH2) with sp2 hybridization has an ideal bond angle of 120°. 2. The second carbon (CH) with sp2 hybridization has an ideal bond angle of 120°. 3. The third carbon (C) with sp2 hybridization also has an ideal bond angle of 120°. 4. The fourth carbon (CH3) with sp3 hybridization has an ideal bond angle of 109.5°. In conclusion, the ideal bond angles for the carbon atoms in the given molecule are 120° for the first, second, and third carbons, and 109.5° for the fourth carbon. The hybridization of orbitals for each carbon is sp2 for the first three carbons and sp3 for the fourth carbon.