Write a balanced chemical equation for the reaction that occurs when (a) titanium metal reacts with \(\mathrm{O}_{2}(g) ;(\mathbf{b})\) silver(I) oxide decomposes into silver metal and oxygen gas when heated; (c) propanol, \(\mathrm{C}_{3} \mathrm{H}_{7} \mathrm{OH}(l)\) burns in air; \((\mathbf{d})\) methyl tert-butyl ether, \(\mathrm{C}_{5} \mathrm{H}_{12} \mathrm{O}(l),\) burns in air.

Short Answer

Expert verified
The balanced equations for the given reactions are: a) \(Ti(s) + O_{2}(g) \rightarrow TiO_{2}(s)\) b) \(2 Ag_{2}O(s) \rightarrow 4Ag(s) + O_{2}(g)\) c) \(2 C_{3}H_{7}OH(l) + 9 O_{2}(g) \rightarrow 6 CO_{2}(g) + 8 H_{2}O(l)\) d) \(C_{5}H_{12}O(l) + 8 O_{2}(g) \rightarrow 5 CO_{2}(g) + 6 H_{2}O(l)\)

Step by step solution

01

Write the basic unbalanced equation

In this reaction, Titanium (Ti) reacts with oxygen gas (O2) to form Titanium dioxide (TiO2). The unbalanced equation is: Ti(s) + O2(g) -> TiO2(s)
02

Balance the equation

As the equation is already balanced with coefficients 1:1:1, the final balanced equation is: Ti(s) + O2(g) -> TiO2(s) #b) Silver(I) oxide decomposes into silver metal and oxygen gas when heated#
03

Write the basic unbalanced equation

In this reaction, Silver(I) oxide (Ag2O) decomposes into silver metal (Ag) and oxygen gas (O2) when heated. The unbalanced equation is: Ag2O(s) -> Ag(s) + O2(g)
04

Balance the equation

To balance the equation, introduce the coefficients 2 for Ag and 1/2 for O2: Ag2O(s) -> 2Ag(s) + 1/2 O2(g)
05

Remove fractional coefficients

To remove the fractional coefficients, multiply all coefficients by 2: 2 Ag2O(s) -> 4Ag(s) + O2(g) #c) Propanol C3H7OH(l) burns in air#
06

Write the basic unbalanced equation

In this reaction, Propanol (C3H7OH) reacts with oxygen gas (O2) to form carbon dioxide (CO2) and water (H2O). The unbalanced equation is: C3H7OH(l) + O2(g) -> CO2(g) + H2O(l)
07

Balance the equation

To balance the equation, introduce coefficients for each species: C3H7OH(l) + 4.5 O2(g) -> 3 CO2(g) + 4 H2O(l)
08

Remove fractional coefficients

To remove the fractional coefficients, multiply all coefficients by 2: 2 C3H7OH(l) + 9 O2(g) -> 6 CO2(g) + 8 H2O(l) #d) Methyl tert-butyl ether C5H12O(l) burns in air#
09

Write the basic unbalanced equation

In this reaction, Methyl tert-butyl ether (C5H12O) reacts with oxygen gas (O2) to form carbon dioxide (CO2) and water (H2O). The unbalanced equation is: C5H12O(l) + O2(g) -> CO2(g) + H2O(l)
10

Balance the equation

To balance the equation, introduce coefficients for each species: C5H12O(l) + 8 O2(g) -> 5 CO2(g) + 6 H2O(l) The balanced equations for the given reactions are: a) Ti(s) + O2(g) -> TiO2(s) b) 2 Ag2O(s) -> 4Ag(s) + O2(g) c) 2 C3H7OH(l) + 9 O2(g) -> 6 CO2(g) + 8 H2O(l) d) C5H12O(l) + 8 O2(g) -> 5 CO2(g) + 6 H2O(l)

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