Washing soda, a compound used to prepare hard water for washing laundry, is a hydrate, which means that a certain number of water molecules are included in the solid structure. Its formula can be written as $\mathrm{Na}_{2} \mathrm{CO}_{3} \cdot \mathrm{xH}_{2} \mathrm{O},\( where \)x$ is the number of moles of \(\mathrm{H}_{2} \mathrm{O}\) per mole of $\mathrm{Na}_{2} \mathrm{CO}_{3} .$ When a 2.558-g sample of washing soda is heated at \(125^{\circ} \mathrm{C},\) all the water of hydration is lost, leaving $0.948 \mathrm{~g}\( of \)\mathrm{Na}_{2} \mathrm{CO}_{3} .\( What is the value of \)\chi ?$

Short Answer

Expert verified
The value of x in the washing soda formula \(\mathrm{Na}_{2} \mathrm{CO}_{3} \cdot \mathrm{xH}_{2} \mathrm{O}\) is approximately 10. Therefore, the washing soda formula can be written as \(\mathrm{Na}_{2} \mathrm{CO}_{3} \cdot 10\mathrm{H}_{2} \mathrm{O}\).

Step by step solution

01

Find the mass of water in the original sample

The mass of water in the original sample can be determined by subtracting the mass of anhydrous \(\mathrm{Na}_{2} \mathrm{CO}_{3}\) from the initial mass of the washing soda. Total mass of sample = 2.558 g Mass of anhydrous \(\mathrm{Na}_{2} \mathrm{CO}_{3}\) = 0.948 g Mass of water = 2.558 g - 0.948 g Mass of water = 1.610 g
02

Calculate the moles of anhydrous \(\mathrm{Na}_{2}\mathrm{CO}_{3}\) and H\(_{2}\)O

Now we need to calculate the moles of anhydrous \(\mathrm{Na}_{2}\mathrm{CO}_{3}\) and H\(_{2}\)O in the sample. The molar mass of \(\mathrm{Na}_{2}\mathrm{CO}_{3}\) = (2 x 22.99 g/mol) + (1 x 12.01 g/mol) + (3 x 16.00 g/mol) = 105.99 g/mol Moles of anhydrous \(\mathrm{Na}_{2}\mathrm{CO}_{3}\) = mass of anhydrous \(\mathrm{Na}_{2} \mathrm{CO}_{3}\) / molar mass of anhydrous \(\mathrm{Na}_{2} \mathrm{CO}_{3}\) Moles of anhydrous \(\mathrm{Na}_{2}\mathrm{CO}_{3}\) = 0.948 g / 105.99 g/mol = 0.008950 mol The molar mass of water (H\(_{2}\)O) = (2 x 1.01 g/mol) + (1 x 16.00 g/mol) = 18.02 g/mol Moles of water (H\(_{2}\)O) = mass of water / molar mass of water Moles of water (H\(_{2}\)O) = 1.610 g / 18.02 g/mol = 0.08939 mol
03

Calculate the value of x

Now, we need to calculate the value of x in the washing soda formula \(\mathrm{Na}_{2} \mathrm{CO}_{3} \cdot \mathrm{xH}_{2} \mathrm{O},\) by using the stoichiometric ratio. x = moles of water (H\(_{2}\)O) / moles of anhydrous \(\mathrm{Na}_{2} \mathrm{CO}_{3}\) x = 0.08939 mol / 0.008950 mol x ≈ 10 Now we know the value of x in the washing soda formula, which is approximately 10. Therefore, the washing soda formula can be written as \(\mathrm{Na}_{2} \mathrm{CO}_{3} \cdot 10\mathrm{H}_{2} \mathrm{O}\).

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