Ignoring protolysis reactions (i.e. proton transfer reaction), specify what ions are present in a solution upon dissolving each of the following substances in water: (a) \(\mathrm{Li}_{2} \mathrm{CO}_{3},\) (b) \((\mathrm{NH} 4)_{3} \mathrm{PO}_{4}\) (d) \(\mathrm{NaPF}_{6^{\circ}}\) (c) \(\mathrm{Na}_{2} \mathrm{Cr}_{2} \mathrm{O}_{7}\)

Short Answer

Expert verified
In summary, the ions present in the solutions upon dissolving the given substances in water are: (a) \(Li_2CO_3\): Li+ and CO3^2- ions (b) \((NH_4)_3PO_4\): NH4+ and PO4^3- ions (c) \(NaPF_6\): Na+ and PF6^- ions (d) \(Na_2Cr_2O_7\): Na+ and Cr2O7^2- ions

Step by step solution

01

a) Li2CO3

In order to determine the ions produced when lithium carbonate (Li2CO3) is dissolved in water, we first look at the compound's formula. From this, we can extract the following ions: - Lithium ion (Li+) appears twice in the formula. Therefore, 2 Li+ ions will be produced per one unit of Li2CO3 dissolved. - Carbonate ion (CO3^2-) appears once in the compound. Upon dissolving Li2CO3 in water, the solution will contain Li+ ions and CO3^2- ions.
02

b) (NH4)3PO4

To find the ions formed when ammonium phosphate ((NH4)3PO4) dissolves in water, we will observe the compound formula. Based on this, we get: - Ammonium ion (NH4+) appears thrice. As a result, every (NH4)3PO4 molecule dissolved will create 3 NH4+ ions. - Phosphate ion (PO4^3-) is present once in the compound. When (NH4)3PO4 is dissolved in water, NH4+ ions and PO4^3- ions will be generated.
03

c) NaPF6

In order to discern the ions comprising the sodium hexafluorophosphate (NaPF6) when dissolved in water, we need to dissect its formula. Per the formula, we have: - Sodium ion (Na+) is present once in the compound. - Hexafluorophosphate ion (PF6^-) is also present once in the compound. So, when NaPF6 is dissolved in water, the solution will have Na+ ions and PF6^- ions.
04

d) Na2Cr2O7

Lastly, we need to identify the ions present when sodium dichromate (Na2Cr2O7) dissolves. By examining its formula, we can identify the following ions: - Sodium ion (Na+) appears twice in the compound. Consequently, 2 Na+ ions will be formed per one molecule of Na2Cr2O7. - Dichromate ion (Cr2O7^2-) is present once in the compound. Upon dissolving Na2Cr2O7 in water, the solution will contain Na+ ions and Cr2O7^2- ions.

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Most popular questions from this chapter

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