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Chapter 4: Problem 22

Predict whether each of the following compounds is solu- ble in water: (a) $\mathrm{MgS},(\mathbf{b}) \mathrm{Cr}(\mathrm{OH})_{3},(\mathbf{c}) \mathrm{Zn} \mathrm{Cl}_{2}$ (d) \(\mathrm{Pb}_{3}\left(\mathrm{PO}_{4}\right)_{2}\) (e) \(\mathrm{Sr}\left(\mathrm{CH}_{3} \mathrm{COO}\right)_{2}\)

Short Answer

Expert verified
The solubility of the given compounds in water is as follows: (a) MgS is soluble, (b) Cr(OH)₃ is insoluble, (c) ZnCl₂ is soluble, (d) Pb₃(PO₄)₂ is insoluble, (e) Sr(CH₃COO)₂ is soluble.

Step by step solution

01

Compound (a): MgS

According to Rule 6, most sulfides are insoluble, except those of alkali metals, alkaline earth metals, and ammonium. Magnesium (Mg) is an alkaline earth metal. Therefore, MgS is soluble in water.
02

Compound (b): Cr(OH)₃

According to Rule 5, most hydroxides are insoluble, except those of alkali metals, ammonium, and heavier alkaline earth metals (calcium, strontium, barium). Chromium (Cr) is not an alkali metal, ammonium, or a heavier alkaline earth metal, so Cr(OH)₃ is insoluble in water.
03

Compound (c): ZnCl₂

According to Rule 3, most chloride, bromide, and iodide salts are soluble, except those of silver, lead(II), and mercury(I). Zinc (Zn) is not one of the exceptions, so ZnCl₂ is soluble in water.
04

Compound (d): Pb₃(PO₄)₂

According to Rule 7, most carbonate, chromate, phosphate, and oxalate salts are insoluble, except those of alkali metals and ammonium. Lead (Pb) is not an alkali metal or ammonium, so Pb₃(PO₄)₂ is insoluble in water.
05

Compound (e): Sr(CH₃COO)₂

According to Rule 2, most acetates are soluble. Strontium (Sr) is not an exception, so Sr(CH₃COO)₂ is soluble in water.

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Most popular questions from this chapter

Pure acetic acid, known as glacial acetic acid, is a liquid with a density of \(1.049 \mathrm{~g} / \mathrm{mL}\) at \(25^{\circ} \mathrm{C}\). Calculate the molarity of a solution of acetic acid made by dissolving \(20.00 \mathrm{~mL}\) of glacial acetic acid at \(25^{\circ} \mathrm{C}\) in enough water to make \(250.0 \mathrm{~mL}\) of solution.

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