Will precipitation occur when the following solutions are mixed? If so, write a balanced chemical equation for the reac- tion. (a) \(\mathrm{Ca}\left(\mathrm{CH}_{3} \mathrm{COO}\right)_{2}\) and \(\mathrm{NaOH},(\mathbf{b}) \mathrm{K}_{2} \mathrm{CO}_{3}\) and \(\mathrm{NH}_{4} \mathrm{NO}_{3}\), (c) \(\mathrm{Na}_{2} \mathrm{~S}\) and \(\mathrm{FeCl}_{3}\)

Short Answer

Expert verified
(a) Precipitation occurs, the balanced chemical equation is: \[\mathrm{Ca}\left(\mathrm{CH}_{3} \mathrm{COO}\right)_{2}+2\mathrm{NaOH}\longrightarrow\mathrm{Ca(OH)_2}+\mathrm{2Na}\left(\mathrm{CH}_{3} \mathrm{COO}\right)\] (b) No precipitation occurs (c) Precipitation occurs, the balanced chemical equation is: \[\mathrm{2Na}_{2} \mathrm{S}+3\mathrm{FeCl}_{3}\longrightarrow6\mathrm{NaCl}+\mathrm{2FeS}\]

Step by step solution

01

Identifying the potential products

We will begin by predicting the products formed from the reaction of the given solutions in part (a) \(\mathrm{Ca}\left(\mathrm{CH}_{3} \mathrm{COO}\right)_{2}\) and \(\mathrm{NaOH}\), part (b) \(\mathrm{K}_{2} \mathrm{CO}_{3}\) and \(\mathrm{NH}_{4} \mathrm{NO}_{3}\), and part (c) \(\mathrm{Na}_{2} \mathrm{~S}\) and \(\mathrm{FeCl}_{3}\). Note that these are double displacement reactions.
02

Check the solubility rules

Now, we will apply the solubility rules to determine if any of the potential products formed are insoluble (forming a precipitate). (a) Starting with \(\mathrm{Ca}\left(\mathrm{CH}_{3} \mathrm{COO}\right)_{2}\) and \(\mathrm{NaOH}\): The potential products are: \(\mathrm{Ca(OH)_2}\) and \(\mathrm{Na}\left(\mathrm{CH}_{3} \mathrm{COO}\right)\) Solubility rules: \(\mathrm{Ca(OH)_2}\): calcium hydroxide is considered slightly soluble in water, thus forming a precipitate \(\mathrm{Na}\left(\mathrm{CH}_{3} \mathrm{COO}\right)\): sodium salts are soluble in water The balanced chemical equation is: \[\mathrm{Ca}\left(\mathrm{CH}_{3} \mathrm{COO}\right)_{2}+2\mathrm{NaOH}\longrightarrow\mathrm{Ca(OH)_2}+\mathrm{2Na}\left(\mathrm{CH}_{3} \mathrm{COO}\right)\] (b) Moving on to \(\mathrm{K}_{2} \mathrm{CO}_{3}\) and \(\mathrm{NH}_{4} \mathrm{NO}_{3}\): The potential products are: \(\mathrm{KNO_3}\) and \(\mathrm{NH_4}\mathrm{(CO_{3})}\) Solubility rules: \(\mathrm{KNO_3}\): potassium salts are soluble in water \(\mathrm{NH_4}\mathrm{(CO_{3})}\): ammonium salts are soluble in water In this case, no precipitation occurs. (c) Finally, \(\mathrm{Na}_{2} \mathrm{S}\) and \(\mathrm{FeCl}_{3}\): The potential products are: \(\mathrm{NaCl}\) and \(\mathrm{FeS}\) Solubility rules: \(\mathrm{NaCl}\): sodium salts are soluble in water \(\mathrm{FeS}\): Metal sulfides, in general are insoluble, including \(\mathrm{FeS}\) which forms a precipitate The balanced chemical equation is: \[\mathrm{2Na}_{2} \mathrm{S}+3\mathrm{FeCl}_{3}\longrightarrow6\mathrm{NaCl}+\mathrm{2FeS}\]
03

Summarize the results

Now we can summarize the results for the given parts: (a) Precipitation occurs, the balanced chemical equation is: \[\mathrm{Ca}\left(\mathrm{CH}_{3} \mathrm{COO}\right)_{2}+2\mathrm{NaOH}\longrightarrow\mathrm{Ca(OH)_2}+\mathrm{2Na}\left(\mathrm{CH}_{3} \mathrm{COO}\right)\] (b) No precipitation occurs (c) Precipitation occurs, the balanced chemical equation is: \[\mathrm{2Na}_{2} \mathrm{S}+3\mathrm{FeCl}_{3}\longrightarrow6\mathrm{NaCl}+\mathrm{2FeS}\]

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