An aqueous solution of an unknown solute is tested with litmus paper and found to be acidic. The solution is weakly conducting compared with a solution of \(\mathrm{NaCl}\) of the same concentration. Which of the following substances could the unknown be: \(\mathrm{KOH}\), $\mathrm{NH}_{3}, \mathrm{HNO}_{3}, \mathrm{KClO}_{2}, \mathrm{H}_{3} \mathrm{PO}_{3}, \mathrm{CH}_{3} \mathrm{COCH}_{3}$ (acetone)?

Short Answer

Expert verified
The unknown substance could be \(\mathrm{H}_{3} \mathrm{PO}_{3}\) (phosphorous acid), as it is acidic and a weak electrolyte.

Step by step solution

01

Eliminate non-acidic compounds

As we know that the solution is acidic, we can start by eliminating any substance that is not acidic or does not produce acidic solutions: 1. KOH: A strong base, not acidic. 2. NH3: A weak base, not acidic. So now, our list of possible substances is: HNO3, KClO2, H3PO3, or acetone (CH3COCH3).
02

Eliminate strong acids

Since the solution is weakly conducting, it indicates that the solute is a weak electrolyte. Thus, strong acids can't be the unknown substance: 1. HNO3: A strong acid (strong electrolyte), not a weakly conducting substance. Now, our list of possible substances is: KClO2, H3PO3, or acetone (CH3COCH3).
03

Investigate remaining substances

Finally, we will evaluate the remaining substances regarding their acidic nature and weakly-conducting property: 1. \(\mathrm{KClO}_{2}\) - When dissolved in water, it forms a neutral solution, so it can't be our unknown substance. 2. \(\mathrm{H}_{3} \mathrm{PO}_{3}\) - Phosphorous acid (H3PO3) is a weak acid (weak electrolyte), so it fits the criteria of being acidic and weakly conducting. 3. \(\mathrm{CH}_{3} \mathrm{COCH}_{3}\) - Acetone is a weakly-conducting organic compound that does not act as an acid when dissolved in water, so it can't be our unknown substance. So based on the given properties, the unknown substance could be: \(\mathrm{H}_{3} \mathrm{PO}_{3}\) (phosphorous acid).

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Most popular questions from this chapter

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