Determine the oxidation number for the indicated element in each of the following substances: (a) \(\mathrm{N}\) in \(\mathrm{N}_{2} \mathrm{H}_{4}\), (b) \(\mathrm{Nin} \mathrm{NO}_{2}\), (c) \(\mathrm{Mn}\) in \(\mathrm{MnCl}_{3}\) (d) Fe in \(\mathrm{FeSO}_{4^{\prime}}\) (e) \(\mathrm{Pt}\) in \(\mathrm{PtCl}_{4}\) (f) \(\mathrm{Cl}\) in \(\mathrm{NaClO}_{4}\).

Short Answer

Expert verified
The oxidation numbers for the indicated elements in the following substances are: (a) N in \(\mathrm{N}_{2} \mathrm{H}_{4}\) is -2, (b) N in \(\mathrm{NO}_{2}\) is +4, (c) Mn in \(\mathrm{MnCl}_{3}\) is +3, (d) Fe in \(\mathrm{FeSO}_{4}\) is +2, (e) Pt in \(\mathrm{PtCl}_{4}\) is +4, and (f) Cl in \(\mathrm{NaClO}_{4}\) is +7.

Step by step solution

01

Use rule 2 and the known oxidation numbers of hydrogen

Since hydrogen typically has an oxidation number of +1, and there are four hydrogen atoms in the compound, the sum of the oxidation numbers for hydrogen is +4. Since the compound is neutral, the sum of the oxidation numbers for nitrogen must be -4. There are two nitrogen atoms, so the oxidation number of each nitrogen atom is -2. (b) Determine the oxidation number of N in \(\mathrm{NO}_{2}\)
02

Use rule 2 and the known oxidation numbers of oxygen

Oxygen typically has an oxidation number of -2, and there are two oxygen atoms in the compound, so the sum of the oxidation numbers for oxygen is -4. Since the compound is neutral, the oxidation number of nitrogen must be +4. (c) Determine the oxidation number of Mn in \(\mathrm{MnCl}_{3}\)
03

Use rule 2 and the known oxidation numbers of chlorine

Chlorine typically has an oxidation number of -1, and there are three chlorine atoms in the compound, so the sum of the oxidation numbers for chlorine is -3. Since the compound is neutral, the oxidation number of manganese must be +3. (d) Determine the oxidation number of Fe in \(\mathrm{FeSO}_{4}\)
04

Use rule 3 and the known oxidation numbers of oxygen, sulfur, and the charge of the polyatomic ion

First, note that sulfate ion, \(SO_{4}^{2-}\), is a polyatomic ion with a charge of -2. The oxidation number of oxygen is -2, and there are four of them, contributing an oxidation number of -8. In the sulfate ion, the oxidation number of sulfur must be +6 to make the sum of the oxidation numbers equal to -2. Now, use the neutral compound rule (rule 2) for \(\mathrm{FeSO}_{4}\). The oxidation numbers of all other elements sum to -2, so the oxidation number of iron must be +2. (e) Determine the oxidation number of Pt in \(\mathrm{PtCl}_{4}\)
05

Use rule 2 and the known oxidation numbers of chlorine

Chlorine typically has an oxidation number of -1, and there are four chlorine atoms in the compound, so the sum of the oxidation numbers for chlorine is -4. Since the compound is neutral, the oxidation number of platinum must be +4. (f) Determine the oxidation number of Cl in \(\mathrm{NaClO}_{4}\)
06

Use rule 2 and the known oxidation numbers of sodium, oxygen, and the charge of the polyatomic ion

Sodium, an alkali metal, has an oxidation number of +1. There is an oxygen atom bonded to a more electronegative chlorine atom in the \(\mathrm{ClO}_{4}\) ion, so the oxidation number of oxygen is still -2. The compound is neutral, and the sum of the oxidation numbers for sodium, oxygen, and the other chlorine atoms in the perchlorate ion is -7, so the oxidation number of the central chlorine atom must be +7.

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