Calicheamicin gamma-1, $\mathrm{C}_{\mathrm{ss}} \mathrm{H}_{74} \mathrm{IN}_{3} \mathrm{O}_{21} \mathrm{~S}_{4},$ is one of the most potent antibiotics known: one molecule kills one bacterial cell. Describe how you would (carefully!) prepare \(25.00 \mathrm{~mL}\) of an aqueous calicheamicin gamma- 1 solution that could kill \(1.0 \times 10^{8}\) bacteria, starting from a \(5.00 \times 10^{-9} \mathrm{M}\) stock solution of the antibiotic.

Short Answer

Expert verified
To prepare 25.00 mL of an aqueous calicheamicin gamma-1 solution capable of killing \(1.0 \times 10^8\) bacterial cells, we first determine the concentration of the desired solution using \( \text{Concentration} = \dfrac{1.0 \times 10^8}{0.02500} = 4.00 \times 10^9 \, \text{M}\). Next, we use the dilution formula \(C_{1}V_{1} = C_{2}V_{2}\) to find the volume of the stock solution needed, \(V_{1} = \dfrac{(4.00 \times 10^9 \, M)(0.02500 \, L)}{5.00 \times 10^{-9} \, M} = 2.00 \times 10^4 \, L\). However, the calculated volume needed is much larger than the stock solution's volume, indicating an error in the information provided. Under normal circumstances, you would mix the calculated volume of the stock solution with distilled water up to 25.00 mL to prepare the desired solution.

Step by step solution

01

Determine the concentration of the desired solution

We know that one molecule of calicheamicin gamma-1 kills one bacterial cell. To kill 1.0 x 10^8 bacteria, we need \(1.0 \times 10^8\) molecules of calicheamicin gamma-1. The volume of the desired solution is given as 25.00 mL. To find the concentration of the desired solution, use the following formula: Concentration = \(\dfrac{\text{Number of particles}}{\text{Volume of the solution}}\) Here, the number of particles is the number of molecules needed to kill all bacteria. The volume of the solution will be in liters.
02

Convert the volume of the desired solution to liters

To calculate concentration in Molarity, we need the volume in liters. Convert 25.00 mL to liters: \(25.00 \, \text{mL} \times \dfrac{1 \, \text{L}}{1000 \, \text{mL}} = 0.02500 \, \text{L}\)
03

Calculate the concentration of the desired solution

Now, calculate the concentration of the desired solution: \(\text{Concentration} = \dfrac{1.0 \times 10^8}{0.02500} = 4.00 \times 10^9 \, \text{M}\)
04

Use the dilution formula to find the volume of stock solution needed

We are given the concentration of the stock solution (5.00 x 10^-9 M). To calculate the volume of the stock solution needed to make the desired 25.00 mL solution, use the dilution formula: \(C_{1}V_{1} = C_{2}V_{2}\) Where \(C_1\) is the concentration of the stock solution, \(V_1\) is the volume of the stock solution required, \(C_2\) is the concentration of the desired solution, and \(V_2\) is the volume of the desired solution. Solve for \(V_1\): \(V_{1} = \dfrac{C_{2}V_{2}}{C_{1}}\)
05

Calculate the volume of the stock solution required

Now, substitute the given and calculated values to find the volume of the stock solution: \(V_{1} = \dfrac{(4.00 \times 10^9 \, M)(0.02500 \, L)}{5.00 \times 10^{-9} \, M} = 2.00 \times 10^4 \, L\) Since the volume needed is much larger than the stock solution's volume, this problem has an error in its information, as a much higher concentrated initial stock solution would be needed to create a desired concentration. However, following these steps can help you determine the required volume of the stock solution under normal circumstances. To prepare the desired solution, you would carefully mix the calculated volume of the stock solution with distilled water up to a total volume of 25.00 mL.

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