During a deep breath, our lungs expand about \(2.0 \mathrm{~L}\) against an external pressure of \(101.3 \mathrm{kPa}\). How much work is involved in this process (in J)?

Short Answer

Expert verified
The work done during this process is \(-202.6 \mathrm{J}\).

Step by step solution

01

Write the formula for work done

We will use the formula of mechanical work done by a gas in this situation. Work done (W) by a gas during the expansion is given by: W = -P × ΔV where P = external pressure, ΔV = change in volume. We have a negative sign because the work done by the gas on the surroundings is negative as the gas is expanding.
02

Substitute the given values

Now we will substitute the given values in the formula: P = 101.3 kPa = 101.3 × 10^3 Pa (converting kPa to Pa) ΔV = 2.0 L = 2.0 × 10^-3 m³ (converting L to m³) W = -101.3 × 10^3 Pa × 2.0 × 10^-3 m³
03

Calculate the work done

Now, find the work done by multiplying the given values. W = -101.3 × 10^3 × 2.0 × 10^-3 W = -202.6 J The work done during this process is -202.6 J. The negative sign indicates that the work is done by the body, expanding the lungs against the external pressure.

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