The complete combustion of methane, \(\mathrm{CH}_{4}(g)\), to form \(\mathrm{H}_{2} \mathrm{O}(l)\) and \(\mathrm{CO}_{2}(g)\) at constant pressure releases \(890 \mathrm{~kJ}\) of heat per mole of \(\mathrm{CH}_{4}\). (a) Write a balanced thermochemical equation for this reaction. (b) Draw an enthalpy diagram for the reaction.

Short Answer

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(a) The balanced thermochemical equation for the complete combustion of methane is: \( \mathrm{CH}_{4}(g) + 2\mathrm{O}_{2}(g) \longrightarrow \mathrm{CO}_{2}(g) + 2\mathrm{H}_{2}\mathrm{O}(l) \hspace{10mm} \Delta H = -890 \mathrm{~kJ} \). (b) To draw the enthalpy diagram, follow these steps: 1. Label the y-axis as "Enthalpy, H". 2. Draw a horizontal line representing the reactants, and label it "Reactants: \(\mathrm{CH}_4(g) + 2\mathrm{O}_2(g)\)". 3. Draw a lower horizontal line representing the products, and label it "Products: \(\mathrm{CO}_2(g) + 2\mathrm{H}_2\mathrm{O}(l)\)". 4. Connect the reactants and products lines with an arrow pointing downwards to illustrate that heat is released during the reaction. 5. Label the arrow with the heat released: "\(\Delta H = -890 \mathrm{~kJ}\)".

Step by step solution

01

(a) Balanced Thermochemical Equation

The complete combustion of methane involves the reaction of methane with oxygen to produce carbon dioxide and water. We start by writing the unbalanced equation: \( \mathrm{CH}_{4}(g) + \mathrm{O}_{2}(g) \longrightarrow \mathrm{CO}_{2}(g) + \mathrm{H}_{2}\mathrm{O}(l) \) In order to balance the equation, we need to make sure that the number of atoms of each element on the reactant and product sides matches. We have 1 carbon atom, 4 hydrogen atoms, and 2 oxygen atoms on the reactant side, and 1 carbon atom, 2 hydrogen atoms, and 3 oxygen atoms on the product side. To balance the equation, we will perform the following steps: 1. Balance the hydrogen atoms by placing a coefficient of 2 in front of \(\mathrm{H}_{2}\mathrm{O}(l)\): \( \mathrm{CH}_{4}(g) + \mathrm{O}_{2}(g) \longrightarrow \mathrm{CO}_{2}(g) + 2\mathrm{H}_{2}\mathrm{O}(l) \) 2. Balance the oxygen atoms by placing a coefficient of 2 in front of \(\mathrm{O}_{2}(g)\): \( \mathrm{CH}_{4}(g) + 2\mathrm{O}_{2}(g) \longrightarrow \mathrm{CO}_{2}(g) + 2\mathrm{H}_{2}\mathrm{O}(l) \) Now that the chemical equation is balanced, we can include the enthalpy change information: \( \mathrm{CH}_{4}(g) + 2\mathrm{O}_{2}(g) \longrightarrow \mathrm{CO}_{2}(g) + 2\mathrm{H}_{2}\mathrm{O}(l) \hspace{10mm} \Delta H = -890 \mathrm{~kJ} \)
02

(b) Enthalpy Diagram

To draw the enthalpy diagram, we will represent the reactants and products with horizontal lines, where the heights of the lines represent their respective enthalpy levels. The difference between the heights of the reactants and products lines reflects the amount of heat released during the reaction. 1. Label the y-axis as "Enthalpy, H". 2. Draw a horizontal line representing the reactants, and label it "Reactants: \(\mathrm{CH}_4(g) + 2\mathrm{O}_2(g)\)". 3. Draw a lower horizontal line representing the products, and label it "Products: \(\mathrm{CO}_2(g) + 2\mathrm{H}_2\mathrm{O}(l)\)". 4. Connect the reactants and products lines with an arrow pointing downwards to illustrate that heat is released during the reaction. 5. Label the arrow with the heat released: "\(\Delta H = -890 \mathrm{~kJ}\)". The enthalpy diagram should look like: [![Enthalpy Diagram][1]][1] [1]: https://i.stack.imgur.com/k5SRk.png

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Most popular questions from this chapter

A coffee-cup calorimeter of the type shown in Figure 5.18 contains $150.0 \mathrm{~g}\( of water at \)25.2^{\circ} \mathrm{C}\(. A \)200-\mathrm{g}$ block of silver metal is heated to \(100.5^{\circ} \mathrm{C}\) by putting it in a beaker of boiling water. The specific heat of \(\mathrm{Ag}(s)\) is $0.233 \mathrm{~J} /(\mathrm{g} \cdot \mathrm{K})\(. The \)\mathrm{Ag}$ is added to the calorimeter, and after some time the contents of the cup reach a constant temperature of \(30.2^{\circ} \mathrm{C} .(\mathbf{a})\) Determine the amount of heat, in J, lost by the silver block. (b) Determine the amount of heat gained by the water. The specific heat of water is $4.184 \mathrm{~J} /(\mathrm{g} \cdot \mathrm{K}) .(\mathbf{c})$ The difference between your answers for (a) and (b) is due to heat loss through the Styrofoam \(^{\circ}\) cups and the heat necessary to raise the temperature of the inner wall of the apparatus. The heat capacity of the calorimeter is the amount of heat necessary to raise the temperature of the apparatus (the cups and the stopper) by \(1 \mathrm{~K} .\) Calculate the heat capacity of the calorimeter in \(\mathrm{J} / \mathrm{K}\). (d) What would be the final temperature of the system if all the heat lost by the silver block were absorbed by the water in the calorimeter?

Consider a system consisting of the following apparatus, in which gas is confined in one flask and there is a vacuum in the other flask. The flasks are separated by a valve. Assume that the flasks are perfectly insulated and will not allow the flow of heat into or out of the flasks to the surroundings. When the valve is opened, gas flows from the filled flask to the evacuated one. (a) Is work performed during the expansion of the gas? (b) Why or why not? (c) Can you determine the value of \(\Delta E\) for the process?

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