The heat of combustion of fructose, $\mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{6},\( is -2812 \)\mathrm{kJ} / \mathrm{mol}$. If a fresh golden delicious apple weighing \(120 \mathrm{~g}\) contains \(16.0 \mathrm{~g}\) of fructose, what caloric content does the fructose contribute to the apple?

Short Answer

Expert verified
The total caloric content of the fructose in the apple is \((\frac{2812 \mathrm{kJ/mol}}{180.18 \mathrm{g/mol}}) \times 16 \mathrm{g} \times 0.239 \mathrm{kcal/ kJ}\) = 75.3 kcal.

Step by step solution

01

Calculate the number of moles of fructose in the apple

Given mass of fructose in the apple is 16 g. We can calculate the number of moles (n) using the formula: n = mass / molar mass The molar mass of fructose, \(\mathrm{C}_{6} \mathrm{H}_{12}\mathrm{O}_{6}\), is: \(6 \times 12.01 \: (for \: Carbon) + 12 \times 1.01 \: (for \: Hydrogen) + 6 \times 16.00 \: (for \: Oxygen) = 72.06 + 12.12 + 96 = 180.18 \mathrm{g/mol}\) Now, let's find the number of moles of fructose, n = \( \frac{16}{180.18}\)
02

Convert the heat of combustion to energy content per gram of fructose

Heat of combustion of fructose is given as -2812 kJ/mol. To convert this to energy content per gram, we can divide the heat of combustion by the molar mass of fructose. Energy content per gram = \(\frac{2812 \mathrm{kJ/mol}}{180.18 \mathrm{g/mol}}\)
03

Calculate the total energy content of the fructose present in the apple

Now that we know the energy content per gram of fructose and the number of moles of fructose present in the apple, we can calculate the total energy content by multiplying these values: Total energy content = Energy content per gram × mass of fructose = \( (\frac{2812 \mathrm{kJ/mol}}{180.18 \mathrm{g/mol}}) \times 16 \mathrm{g}\) Finally, as 1 kJ is equal to 0.239 kcal, we can convert our final answer in kJ to kcal: Total caloric content = Total energy content in kJ × 0.239 kcal / kJ

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Most popular questions from this chapter

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