Titanium metal requires light with a maximum wavelength of \(286 \mathrm{nm}\) to emit electrons. (a) What is the minimum energy of the photons necessary to emit electrons from titanium via the photoelectric effect? (b) What is the frequency of this radiation? (c) Is it possible to eject electrons from titanium metal using infrared light? (d) If titanium is irradiated with light of wavelength \(276 \mathrm{nm}\), what is the maximum possible kinetic energy of the emitted electrons?

(a) The minimum energy of the photons necessary to emit electrons from titanium via the photoelectric effect is \(E = 6.63 \times 10^{-34} \mathrm{Js} \times \frac{3.0 \times 10^8 \mathrm{m/s}}{286 \times 10^{-9} \mathrm{m}}\). (b) The frequency of this radiation is \(\nu = \frac{3.0 \times 10^8 \mathrm{m/s}}{286 \times 10^{-9} \mathrm{m}}\). (c) It is not possible to eject electrons from titanium metal using infrared light as the maximum wavelength of infrared light (700 nm) is greater than the given wavelength of 286 nm. (d) To find the maximum possible kinetic energy of emitted electrons, first calculate the energy of photons at wavelength \(276 \mathrm{nm}\), \(E_2 = 6.63 \times 10^{-34} \mathrm{Js} \times \frac{3.0 \times 10^8 \mathrm{m/s}}{276 \times 10^{-9} \mathrm{m}}\). Then, the maximum possible kinetic energy is \(K = E_2 - E\).