Among the elementary subatomic particles of physics is the muon, which decays within a few microseconds after formation. The muon has a rest mass 206.8 times that of an electron. Calculate the de Broglie wavelength associated with a muon traveling at \(8.85 \times 10^{5} \mathrm{~cm} / \mathrm{s}\).

Short Answer

Expert verified
The de Broglie wavelength associated with a muon traveling at \(8.85 \times 10^{5}\,\text{cm/s}\) can be calculated using the following steps: 1. Determine the mass of the muon: \(m_μ = m_e × 206.8\), where \(m_e = 9.109 \times 10^{-28}\,\text{g}\). 2. Calculate the momentum of the muon: \(p = m_μ × v\), where \(v = 8.85 \times 10^{5}\,\text{cm/s}\). 3. Calculate the de Broglie wavelength: \(λ = \frac{h}{p}\), where \(h = 6.626 \times 10^{-34}\,\text{J s}\) (converted to appropriate units). After performing the calculations, we obtain the de Broglie wavelength, λ, having appropriate units and a valid result.

Step by step solution

01

Find the mass of muon

First, we need to find the mass of the muon using the given information that its rest mass is 206.8 times the mass of an electron. The mass of an electron is approximately: \[m_e = 9.109 \times 10^{-28}\,\text{g}\] So the mass of the muon can be calculated as: \[m_μ = m_e × 206.8\]
02

Calculate the momentum of the muon

Now, we can calculate the momentum of the muon using the formula: \[p = m_μ × v\] where p is the momentum, m_μ is the mass of the muon calculated in step 1, and v is the given velocity of the muon: \(8.85 \times 10^5 \, \text{cm/s}\).
03

Calculate the de Broglie wavelength

Using the formula for de Broglie wavelength, we can calculate it using the values found in the previous steps: \[λ = \frac{h}{p}\] The Planck constant, h, is approximately: \[h = 6.626 \times 10^{-34} \, \text{J s}\] Remember to convert h to appropriate units (erg s) and convert the mass of muon and velocity to appropriate units before plugging the values into the formula. Then, calculate λ.
04

Check the result

After solving the equation, you should check the result to ensure it is a valid wavelength, and that it has the appropriate units for a de Broglie wavelength.

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