What is the maximum number of electrons that can occupy each of the following subshells? (a) \(3 s,(\) b) \(2 p,(\mathbf{c}) 4 d\), (d) \(5 s\).

Short Answer

Expert verified
The maximum number of electrons that can occupy each subshell are: (a) 3s: 2 electrons, (b) 2p: 6 electrons, (c) 4d: 10 electrons, and (d) 5s: 2 electrons.

Step by step solution

01

Identify the quantum numbers for each subshell

To identify the quantum numbers, we need to know the principal quantum number (n) and the letters corresponding to the orbital angular momentum quantum number (l). Here, s, p, d, and f represent l = 0, 1, 2, and 3, respectively. (a) 3s: n = 3 and l = 0 (b) 2p: n = 2 and l = 1 (c) 4d: n = 4 and l = 2 (d) 5s: n = 5 and l = 0
02

Calculate the number of electrons for each subshell

Now, use the formula: Number of electrons = 2(2l + 1) to find the maximum number of electrons that can occupy each subshell. (a) 3s: Number of electrons = 2(2(0) + 1) = 2 (b) 2p: Number of electrons = 2(2(1) + 1) = 6 (c) 4d: Number of electrons = 2(2(2) + 1) = 10 (d) 5s: Number of electrons = 2(2(0) + 1) = 2
03

State the maximum number of electrons for each subshell

(a) The maximum number of electrons that can occupy the 3s subshell is 2. (b) The maximum number of electrons that can occupy the 2p subshell is 6. (c) The maximum number of electrons that can occupy the 4d subshell is 10. (d) The maximum number of electrons that can occupy the 5s subshell is 2.

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Most popular questions from this chapter

Consider a transition in which the electron of a hydrogen atom is excited from \(n=1\) to \(n=\infty\). (a) What is the end result of this transition? (b) What is the wavelength of light that must be absorbed to accomplish this process? (c) What will occur if light with a shorter wavelength than that in part (b) is used to excite the hydrogen atom? (d) How are the results of parts \((\mathrm{b})\) and \((\mathrm{c})\) related to the plot shown in Exercise \(6.88 ?\)

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