The following electron configurations represent excited states. Identify the element and write its ground-state condensed electron configuration. (a) \(1 s^{2} 2 s^{2} 2 p^{4} 3 s^{1}\) (b) \([\mathrm{Ne}] 3 s^{1} 3 p^{4} 4 p^{1}\) (c) \([\mathrm{Ar}] 4 s^{2} 3 d^{6} 4 p^{1}\)

Short Answer

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The short answer based on the provided solution is: (a) Fluorine (F): \(1 s^2 2 s^2 2 p^6 3 s^1\) (b) Sulfur (S): \([\mathrm{Ne}]3 s^2 3 p^6\) (c) Cobalt (Co): \([\mathrm{Ar}] 4 s^2 3 d^{10} 4 p^1\)

Step by step solution

01

(a) Find the total number of electrons

For the given excited state configuration, \(1 s^2 2 s^2 2 p^4 3 s^1\), let's find the total number of electrons. \(1 s^2\) = 2 electrons \(2 s^2\) = 2 electrons \(2 p^4\) = 4 electrons \(3 s^1\) = 1 electron Total number of electrons = 2 + 2 + 4 + 1 = 9 electrons
02

(a) Write the ground-state electron configuration

For 9 electrons, the ground-state electron configuration is: \(1 s^2 2 s^2 2 p^6 3 s^1\)
03

(a) Identify the element

The element with an atomic number (number of protons and electrons) of 9 is fluorine (F).
04

(b) Find the total number of electrons

For the given excited state configuration, \([\mathrm{Ne}] 3 s^1 3 p^4 4 p^1\), let's find the total number of electrons. Neon (Ne) has 10 electrons, so we start there and add the electrons from the configuration. \(3 s^1\) = 1 electron \(3 p^4\) = 4 electrons \(4 p^1\) = 1 electron Total number of electrons = 10 (Ne) + 1 + 4 + 1 = 16 electrons
05

(b) Write the ground-state electron configuration

For 16 electrons, the ground-state electron configuration is: \([\mathrm{Ne}]3 s^2 3 p^6\)
06

(b) Identify the element

The element with an atomic number of 16 is sulfur (S).
07

(c) Find the total number of electrons

For the given excited state configuration, \([\mathrm{Ar}] 4 s^2 3 d^6 4 p^1\), let's find the total number of electrons. Argon (Ar) has 18 electrons, so we start there and add the electrons from the configuration. \(4 s^2\) = 2 electrons \(3 d^6\) = 6 electrons \(4 p^1\) = 1 electron Total number of electrons = 18 (Ar) + 2 + 6 + 1 = 27 electrons
08

(c) Write the ground-state electron configuration

For 27 electrons, the ground-state electron configuration is: \([\mathrm{Ar}] 4 s^2 3 d^{10} 4 p^1\)
09

(c) Identify the element

The element with an atomic number of 27 is cobalt (Co). To summarize, the ground-state condensed electron configurations for the given excited state configurations are: (a) Fluorine (F): \(1 s^2 2 s^2 2 p^6 3 s^1\) (b) Sulfur (S): \([\mathrm{Ne}]3 s^2 3 p^6\) (c) Cobalt (Co): \([\mathrm{Ar}] 4 s^2 3 d^{10} 4 p^1\)

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Most popular questions from this chapter

The first 25 years of the twentieth century were momentous for the rapid pace of change in scientists' understanding of the nature of matter. (a) How did Rutherford's experiments on the scattering of \(\alpha\) particles by a gold foil set the stage for Bohr's theory of the hydrogen atom? (b) In what ways is de Broglie's hypothesis, as it applies to electrons, consistent with J. J. Thomson's conclusion that the electron has mass? In what sense is it consistent with proposals preceding Thomson's work that the cathode rays are a wave phenomenon?

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