Using only the periodic table, arrange each set of atoms in (a) \(\mathrm{Cs}\), Se, Te; order of increasing radius: (b) \(\mathrm{S}, \mathrm{Si}, \mathrm{Sr} ;\) (c) P, Po, Pb.

Short Answer

Expert verified
a) \(Se < Te < Cs\) b) \(Si < S < Sr\) c) \(P < Po < Pb\)

Step by step solution

01

Locate the Elements on the Periodic Table

Using the periodic table, find the positions of Cs (Cesium), Se (Selenium), and Te (Tellurium). Cs is in Group 1 and Period 6, Se is in Group 16 and Period 4, and Te is in Group 16 and Period 5.
02

Compare the Positions

Notice that Se and Te are in the same group but in different periods, so Te has a larger atomic radius than Se. Cs is in Group 1 and is in a period lower than Te, so it has the largest atomic radius among the three elements.
03

Arrange the Elements

Therefore, the order of increasing atomic radius is: Se, Te, Cs b) Arrange S, Si, and Sr in the order of increasing radius:
04

Locate the Elements on the Periodic Table

Using the periodic table, find the positions of S (Sulfur), Si (Silicon), and Sr (Strontium). S is in Group 16 and Period 3, Si is in Group 14 and Period 3, and Sr is in Group 2 and Period 5.
05

Compare the Positions

Sulfur and Silicon are in the same period but different groups. Since the atomic radius decreases across a period, S has a larger atomic radius than Si. Sr is in Group 2 and a period lower than Sulfur and Silicon, so Sr has the largest atomic radius among the three elements.
06

Arrange the Elements

Therefore, the order of increasing atomic radius is: Si, S, Sr c) Arrange P, Po, and Pb in the order of increasing radius:
07

Locate the Elements on the Periodic Table

Using the periodic table, find the positions of P (Phosphorus), Po (Polonium), and Pb (Lead). P is in Group 15 and Period 3, Po is in Group 16 and Period 6, and Pb is in Group 14 and Period 6.
08

Compare the Positions

Notice that Po and Pb are in the same period but different groups. Since the atomic radius decreases across a period, Po has a smaller atomic radius than Pb. P is in Group 15 in a period higher than Po and Pb, so it has the smallest atomic radius among the three elements.
09

Arrange the Elements

Therefore, the order of increasing atomic radius is: P, Po, Pb

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