Identify each statement as true or false: (a) Cations are larger than their corresponding neutral atoms. (b) \(\mathrm{Li}^{+}\) is smaller than Li. (c) \(\mathrm{Cl}^{-}\) is bigger than I .

Short Answer

Expert verified
(a) False. Cations are smaller than their corresponding neutral atoms, as the loss of electrons results in a stronger attraction towards the nucleus. (b) True. \(\mathrm{Li}^{+}\) is smaller than Li because the ion has lost one electron, resulting in a smaller size. (c) False. The neutral iodine atom has a larger atomic size compared to the \(\mathrm{Cl}^{-}\) anion due to their positions in the Periodic Table.

Step by step solution

01

(Statement a: Cations are larger than their corresponding neutral atoms)

False. Cations are formed when neutral atoms lose one or more electrons, resulting in a positively charged ion. The loss of electrons causes the remaining electrons to experience a stronger attraction towards the nucleus, shrinking the atomic size. Therefore, cations are typically smaller than their corresponding neutral atoms.
02

(Statement b: \(\mathrm{Li}^{+}\) is smaller than Li)

True. Losing an electron in the process of forming a cation generally results in the ion being smaller than the neutral atom. In the case of \(\mathrm{Li}^{+}\), this Li ion has lost one electron, resulting in a smaller size compared to its corresponding neutral state.
03

(Statement c: \(\mathrm{Cl}^{-}\) is bigger than I)

False. This statement is concerning two different elements: chlorine (Cl) and iodine (I). The statement refers to the size of the anion \(\mathrm{Cl}^{-}\) and compares it to the neutral atom of iodine (I). As we move down a group in the Periodic Table, the atomic size increases due to the increased number of electron shells. Since iodine is located below the chlorine in Group 17 (halogens), the neutral iodine atom would have a larger atomic size compared to the neutral chlorine atom. As for the \(\mathrm{Cl}^{-}\) anion, it has gained an extra electron, making it larger than the neutral Cl atom. However, even with the increased size of the anion, the neutral iodine atom would still be larger than the \(\mathrm{Cl}^{-}\) anion, making this statement false.

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Most popular questions from this chapter

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