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Chapter 7: Problem 61

Would you expect zirconium(II) oxide, \(\mathrm{ZrO},\) to react more readily with \(\mathrm{HCl}(a q)\) or \(\mathrm{NaOH}(a q) ?\)

Short Answer

Expert verified
Zirconium(II) oxide (ZrO) is a basic metal oxide, which generally favorably reacts with acids to form salts and water. Thus, it would react more readily with HCl(aq) in the following acid-base reaction: \(ZrO + 2HCl \rightarrow ZrCl_2 + H_2O\).

Step by step solution

01

Determine the nature of the given reactants

First, we need to classify the reactants according to their acid-base properties. HCl(aq) is an acid, while NaOH(aq) is a base. Zirconium(II) oxide (ZrO) is a metal oxide, which generally exhibit basic properties as they can react with acids to form salts and water.
02

Predict the possible reaction products

Next, we predict the products of the possible reactions between ZrO and the given reactants (HCl and NaOH). For the reaction with HCl, since ZrO is a basic oxide, it reacts with the acid to form a salt and water: \(ZrO + 2HCl \rightarrow ZrCl_2 + H_2O\) For the reaction with NaOH, Zirconium(II) oxide (ZrO) can react with a base in a dissolution process, where a complex ion (zirconate ion) is formed: \(ZrO + NaOH + H_2O \rightarrow Na[Zr(OH)_4]\)
03

Determine which reaction is more favorable

Now we need to determine which reaction is more favorable. The reaction between ZrO and HCl forms {ZrCl_2} and water, indicating a typical acid-base reaction. This indicates that ZrO reacts more readily with HCl(aq) because it behaves as a basic oxide, thus favoring the formation of a salt and water.

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Most popular questions from this chapter

In Table 7.8 , the bonding atomic radius of neon is listed as $58 \mathrm{pm},\( whereas that for xenon is listed as \)140 \mathrm{pm}$. A classmate of yours states that the value for Xe is more realistic than the one for Ne. Is she correct? If so, what is the basis for her statement?

Write a balanced equation for the reaction that occurs in each of the following cases: (a) Lithium is added to water. (b) Calcium is added to water. (c) Potassium reacts with chlorine gas. (d) Rubidium reacts with oxygen.

Elements in group 17 in the periodic table are called the halogens; elements in group 16 are called the chalcogens. (a) What is the most common oxidation state of the chalcogens compared to the halogens? (b) For each of the following periodic properties, state whether the halogens or the chalcogens have larger values: atomic radii, ionic radii of the most common oxidation state, first ionization energy, second ionization energy.

Which of the following chemical equations is connected to the definitions of (a) the first ionization energy of oxygen, (b) the second ionization energy of ox ygen, and (c) the electron affinity of oxygen? (i) \(\mathrm{O}(g)+\mathrm{e}^{-} \longrightarrow \mathrm{O}^{-}(g)\) (ii) \(\mathrm{O}(g) \longrightarrow \mathrm{O}^{+}(g)+\mathrm{e}^{-}\) (iii) \(\mathrm{O}(g)+2 \mathrm{e}^{-} \longrightarrow \mathrm{O}^{2-}(g)\) (iv) \(\mathrm{O}(g) \longrightarrow \mathrm{O}^{2+}(g)+2 \mathrm{e}^{-}\) $(\mathbf{v}) \mathrm{O}^{+}(g) \longrightarrow \mathrm{O}^{2+}(g)+\mathrm{e}^{-}$

Consider the \(\mathrm{A}_{2} \mathrm{X}_{4}\) molecule depicted here, where \(\mathrm{A}\) and \(\mathrm{X}\) are elements. The \(A-A\) bond length in this molecule is \(d_{1}\), and the four \(\mathrm{A}-\mathrm{X}\) bond lengths are each \(d_{2}\). (a) In terms of \(d_{1}\) and \(d_{2},\) how could you define the bonding atomic radii of atoms A and X? (b) In terms of \(d_{1}\) and \(d_{2}\), what would you predict for the \(X-X\) bond length of an \(X_{2}\) molecule? [Section \(\left.7.3\right]\)
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