Write balanced equations for the following reactions: (a) boron trichloride with water, (b) cobalt (II) oxide with nitric acid, (c) phosphorus pentoxide with water, (d) carbon dioxide with aqueous barium hydroxide.

In this reaction, boron trichloride (BCl3) reacts with water (H2O). This is an example of a decomposition reaction where boron trichloride hydrolyzes in the presence of water, forming boric acid (H3BO3) and hydrochloric acid (HCl). Step 1. Write the unbalanced equation: BCl3 + H2O → H3BO3 + HCl Step 2. Balancing the equation: To balance the equation, adjust the coefficients such that the number of atoms on the reactant side equals the number of atoms on the product side. BCl3 + 3 H2O → H3BO3 + 3 HCl Hence, the balanced equation for the reaction between boron trichloride and water is BCl3 + 3 H2O → H3BO3 + 3 HCl.

In this reaction, cobalt (II) oxide (CoO) reacts with nitric acid (HNO3). This is a double displacement reaction involving an oxide and an acid, resulting in the formation of a salt, cobalt (II) nitrate (Co(NO3)2), and water (H2O). Step 1. Write the unbalanced equation: CoO + HNO3 → Co(NO3)2 + H2O Step 2. Balancing the equation: To balance the equation, adjust the coefficients such that the number of atoms on the reactant side equals the number of atoms on the product side. CoO + 2 HNO3 → Co(NO3)2 + H2O Hence, the balanced equation for the reaction between cobalt (II) oxide and nitric acid is CoO + 2 HNO3 → Co(NO3)2 + H2O.

In this reaction, phosphorus pentoxide (P4O10) reacts with water (H2O). This is a synthesis reaction resulting in the formation of phosphoric acid (H3PO4). Step 1. Write the unbalanced equation: P4O10 + H2O → H3PO4 Step 2. Balancing the equation: To balance the equation, adjust the coefficients such that the number of atoms on the reactant side equals the number of atoms on the product side. P4O10 + 6 H2O → 4 H3PO4 Hence, the balanced equation for the reaction between phosphorus pentoxide and water is P4O10 + 6 H2O → 4 H3PO4.

In this reaction, carbon dioxide (CO2) reacts with aqueous barium hydroxide (Ba(OH)2). This is another example of a double displacement reaction, resulting in the formation of barium carbonate (BaCO3) and water (H2O). Step 1. Write the unbalanced equation: CO2 + Ba(OH)2 → BaCO3 + H2O Step 2. Balancing the equation: To balance the equation, adjust the coefficients such that the number of atoms on the reactant side equals the number of atoms on the product side. CO2 + Ba(OH)2 → BaCO3 + H2O Here, the equation is already balanced with equal numbers of atoms on both reactant and product sides, so no change is needed in coefficients. Hence, the balanced equation for the reaction between carbon dioxide and aqueous barium hydroxide is CO2 + Ba(OH)2 → BaCO3 + H2O.