Which of the following bonds are polar? (a) \(\mathrm{C}-\mathrm{O}\) (b) \(\mathrm{Sl}-\mathrm{F},(\mathbf{c}) \mathrm{N}-\mathrm{Cl}\) (d) \(\mathrm{C}-\mathrm{Cl}\). Which is the more electronegative atom in each polar bond?

Short Answer

Expert verified
The polar bonds are (a) C-O, (b) Si-F, and (d) C-Cl. The more electronegative atoms in each polar bond are oxygen (O) in C-O, fluorine (F) in Si-F, and chlorine (Cl) in C-Cl. The N-Cl bond is nonpolar.

Step by step solution

01

Electronegativity Values

For reference, here are the electronegativity values of the atoms involved in the given bonds: - Carbon (C): 2.55 - Oxygen (O): 3.44 - Silicon (Si): 1.90 - Fluorine (F): 3.98 - Nitrogen (N): 3.04 - Chlorine (Cl): 3.16
02

Bond (a): C-O

The electronegativity difference between carbon (2.55) and oxygen (3.44) is 0.89. Since this value is greater than 0.5, the C-O bond is polar. The more electronegative atom in this bond is oxygen (O).
03

Bond (b): Si-F

The electronegativity difference between silicon (1.90) and fluorine (3.98) is 2.08. As this value is much larger than 0.5, the Si-F bond is polar. The more electronegative atom in this bond is fluorine (F).
04

Bond (c): N-Cl

The electronegativity difference between nitrogen (3.04) and chlorine (3.16) is 0.12. The difference is smaller than 0.5, so the N-Cl bond is nonpolar.
05

Bond (d): C-Cl

The electronegativity difference between carbon (2.55) and chlorine (3.16) is 0.61. Since this value is larger than 0.5, the C-Cl bond is polar. The more electronegative atom in this bond is chlorine (Cl).
06

Summary

Out of the given bonds, the polar bonds are C-O, Si-F, and C-Cl. The more electronegative atoms in each polar bond are oxygen (O) in C-O, fluorine (F) in Si-F, and chlorine (Cl) in C-Cl. The N-Cl bond is nonpolar as the electronegativity difference is smaller than 0.5.

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