(a) Draw the best Lewis structure(s) for the nitrite ion, \(\mathrm{NO}_{2}^{-}\). (b) With what allotrope of oxygen is it isoelectronic? (c) What would you predict for the lengths of the bonds in \(\mathrm{NO}_{2}^{-}\) relative to \(\mathrm{N}-\mathrm{O}\) single bonds and double bonds?

Short Answer

Expert verified
(a) The best Lewis structures for the nitrite ion, \(\mathrm{NO}_{2}^{-}\), are two resonance structures: (i) N atom connected to one O atom with a double bond, and to another O atom with a single bond, which has an extra lone pair of electrons, and (ii) N atom connected to one O atom with a single bond with an extra lone pair of electrons, and another O atom with a double bond. Both of these structures satisfy the octet rule. (b) The peroxide ion (O\(_2^{2-}\)) is isoelectronic with the nitrite ion, as they both have 18 electrons. (c) In the nitrite ion, the N-O bond lengths will be intermediate between the single bond length found in \(\mathrm{N}-\mathrm{O}\) single bond compounds and the double bond length found in \(\mathrm{N}=\mathrm{O}\) double bond compounds.

Step by step solution

01

Drawing the Lewis structure for nitrite ion

To determine the best Lewis structure(s) for \(\mathrm{NO}_{2}^{-}\), we will first count the total number of valence electrons. Nitrogen has 5 valence electrons, each oxygen atom has 6, and there is an additional electron due to the negative charge. Therefore, the total number of valence electrons is 5 + 6(2) + 1 = 18. Now, we will construct different resonance structures for \(\mathrm{NO}_{2}^{-}\) and verify if they fulfill the octet rule. Two possible structures are: (i) N atom connected to one O atom with a double bond, and to another O atom with a single bond, which has an extra lone pair of electrons. (ii) N atom connected to one O atom with a single bond with an extra lone pair of electrons, and another O atom with a double bond. Both of these structures satisfy the octet rule.
02

Determine the isoelectronic allotrope of oxygen

Isoelectronic species have the same number of electrons. In this case, we have \(5 + 6(2) + 1 = 18\) electrons in the nitrite ion. Now, we need to check which allotrope of oxygen has the same number of electrons. Oxygen exists in various allotropic forms such as O\(_2\) (16 electrons) and O\(_3\) (ozone, 24 electrons). None of these molecules have 18 electrons. However, if we consider a superoxide ion (O\(_2^{-}\)), it has 16 + 1 = 17 electrons, and a peroxide ion (O\(_2^{2-}\)) has 16 + 2 = 18 electrons. Therefore, the peroxide ion (O\(_2^{2-}\)) is isoelectronic with the nitrite ion.
03

Predicting the bond lengths of the nitrite ion

We have two possible Lewis resonance structures for \(\mathrm{NO}_{2}^{-}\), and the actual molecule is a hybrid of these two structures. In resonance hybrid structure, bond lengths are intermediate between single and double bonds. For the nitrite ion, the N-O bond lengths will be intermediate between the single bond length found in \(\mathrm{N}-\mathrm{O}\) single bond compounds and the double bond length found in \(\mathrm{N}=\mathrm{O}\) double bond compounds.

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Most popular questions from this chapter

State whether each of these statements is true or false. (a) The longer the bond, the stronger the bond. (b) \(\mathrm{C}-\mathrm{C}\) bonds are stronger than \(\mathrm{C}-\mathrm{F}\) bonds. (c) A typical double bond length is in the \(500-1000\) pm range. (d) Energy is required to form a chemical bond. (e) The longer the bond, the more energy is stored chemical bonds.

Draw the Lewis structures for each of the following molecules or ions. Identify instances where the octet rule is not obeyed; state which atom in each compound does not follow the octet rule; and state how many electrons surround these atoms: $(\mathbf{a}) \mathrm{PF}_{6}^{-},(\mathbf{b}) \mathrm{BeCl}_{2},(\mathbf{c}) \mathrm{NH}_{3},(\mathbf{d}) \mathrm{XeF}_{2} \mathrm{O}\( (the Xe is the central atom), (e) \)\mathrm{SO}_{4}^{2-}$.

(a) Write the electron configuration for the element titanium, Ti. How many valence electrons does this atom possess? (b) Hafnium, Hf, is also found in group 4. Write the electron configuration for Hf. (c) Ti and Hf behave as though they possess the same number of valence electrons. Which of the subshells in the electron configuration of Hf behave as valence orbitals? Which behave as core orbitals?

(a) Which of these compounds is an exception to the octet rule: carbon dioxide, water, ammonia, phosphorus trifluoride, or arsenic pentafluoride? (b) Which of these compounds or ions is an exception to the octet rule: borohydride \(\left(\mathrm{BH}_{4}^{-}\right),\) borazine $\left(\mathrm{B}_{3} \mathrm{~N}_{3} \mathrm{H}_{6},\right.$ which is analogous to benzene with alternating \(\mathrm{B}\) and \(\mathrm{N}\) in the ring \(),\) or boron trichloride?

(a) Use Lewis symbols to represent the reaction that occurs between Li and O atoms. (b) What is the chemical formula of the most likely product? (c) How many electrons are transferred? (d) Which atom loses electrons in the reaction?

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