(a) An \(\mathrm{AB}_{2}\), molecule is linear. How many nonbonding electron pairs are around the A atom from this information? (b) How many nonbonding electrons surround the Xe in $\mathrm{XeF}_{2} ?(\mathbf{c})\( Is \)\mathrm{XeF}_{2}$ linear?

Short Answer

Expert verified
(a) In a linear AB2 molecule, there are no nonbonding electron pairs around the A atom. (b) There are six nonbonding electrons surrounding the Xe atom in XeF2. (c) Yes, XeF2 is a linear molecule.

Step by step solution

01

(a) Determining nonbonding electron pairs around the A atom in a linear AB2 molecule

According to VSEPR theory, the molecular geometry depends on the number of bonding and nonbonding electron pairs around the central atom. For a linear geometry, there must be two bonding pairs and no lone pairs around the central atom, or two bonding pairs and three lone pairs around the central atom. Since the molecule is linear, there are no nonbonding electron pairs around the A atom.
02

(b) Finding the number of nonbonding electrons surrounding Xe in XeF2

Xenon (Xe) is a noble gas and has 8 electrons in its valence shell. In XeF2, two of Xe's valence electrons will be used for bonding with the fluorine atoms, and the other six valence electrons will remain as nonbonding electrons. Therefore, there are six nonbonding electrons surrounding the Xe atom in XeF2.
03

(c) Checking if XeF2 is a linear molecule

Using the VSEPR theory, we can determine the molecular geometry of XeF2. The Xe atom has 2 bonding pairs (Xe-F) and 3 lone pairs (6 nonbonding electrons). In VSEPR notation, this is AX2E3, where A represents the central atom (Xe), X represents atoms bonded to the central atom (fluorine), and E represents lone pair electrons on the central atom (nonbonding electrons). The AX2E3 molecular shape minimizes electron pair repulsion and results in a linear molecular geometry. Consequently, XeF2 is a linear molecule.

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