How would we describe a substance that contains only paired electrons and is weakly repelled by a magnetic field? Which of the following ions would you expect to possess similar characteristics: $\mathrm{H}_{2}^{-}, \mathrm{Ne}_{2}^{+}, \mathrm{F}_{2}, \mathrm{O}_{2}^{2+} ?$

Short Answer

Expert verified
A substance with only paired electrons and weakly repelled by a magnetic field is called a diamagnetic substance. Out of the given ions \(\mathrm{H}_{2}^{-}, \mathrm{Ne}_{2}^{+}, \mathrm{F}_{2}, \mathrm{O}_{2}^{2+}\), the ions with similar characteristics to a diamagnetic substance are \(\mathrm{H}_{2}^{-}\) and \(\mathrm{F}_{2}\).

Step by step solution

01

Identify the substance with only paired electrons and weak magnetic repulsion

The substance with only paired electrons and weakly repelled by a magnetic field is called a diamagnetic substance. Diamagnetism arises from the presence of all paired electrons in the substance, causing it to be weakly repelled by an external magnetic field.
02

Check the electronic configuration of \(\mathrm{H}_{2}^{-}\) ion

The hydrogen atom has an atomic number of 1, so its electronic configuration is 1s^1. In a covalent bond, H atoms share electrons. In the \(\mathrm{H}_{2}^{-}\) ion, each hydrogen has one electron and gains one more from the extra negative charge, making a total of 2 electrons in bonding. Thus, the electronic configuration of the \(\mathrm{H}_{2}^{-}\) ion is 1s^2, indicating both electrons are paired. This ion has similar characteristics to a diamagnetic substance.
03

Check the electronic configuration of \(\mathrm{Ne}_{2}^{+}\) ion

The neon atom has an atomic number of 10, so its electronic configuration is 1s^2 2s^2 2p^6. In the \(\mathrm{Ne}_{2}^{+}\) ion, one electron is removed from the atom. The new configuration becomes 1s^2 2s^2 2p^5. All electrons are not paired, indicating this ion does not have similar characteristics to a diamagnetic substance.
04

Check the electronic configuration of \(\mathrm{F}_{2}\) ion

The fluorine atom has an atomic number of 9, so its electronic configuration is 1s^2 2s^2 2p^5. In \(\mathrm{F}_{2}\), each fluorine atom shares one electron with the other. Thus, the resulting electron configuration remains the same, with all fluorine electrons being paired: 1s^2 2s^2 2p^6 for each fluorine atom. So, the \(\mathrm{F}_{2}\) molecule has similar characteristics to a diamagnetic substance.
05

Check the electronic configuration of \(\mathrm{O}_{2}^{2+}\) ion

The oxygen atom has an atomic number of 8, so its electronic configuration is 1s^2 2s^2 2p^4. In the \(\mathrm{O}_{2}^{2+}\) ion, two electrons are removed, and the configuration becomes 1s^2 2s^2 2p^3. All electrons are not paired, indicating this ion does not have similar characteristics to a diamagnetic substance.
06

Conclusion

Out of the given ions \(\mathrm{H}_{2}^{-}, \mathrm{Ne}_{2}^{+}, \mathrm{F}_{2}, \mathrm{O}_{2}^{2+}\), the ions with similar characteristics to a substance with only paired electrons and weakly repelled by a magnetic field (diamagnetic) are \(\mathrm{H}_{2}^{-}\) and \(\mathrm{F}_{2}\).

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