In order to conduct three experiments that required different amounts of chloride ions, what mass of a \(0.150 \mathrm{~m}\) \(\mathrm{NaCl}\) solution is needed to obtain (a) \(0.00100 \mathrm{~mol} \mathrm{Cl}^{-}\) (b) \(0.00500 \mathrm{~mol} \mathrm{Cl}\), (c) \(0.0200 \mathrm{~mol} \mathrm{Cl}^{-}\) ?

Short Answer

Expert verified
For 0.00100 mol Cl-, 6.67 mL of the solution is needed, corresponding to 6.67 g. For 0.00500 mol Cl-, 33.33 mL or 33.33 g is needed. For 0.0200 mol Cl-, 133.33 mL or 133.33 g is needed.

Step by step solution

01

Understanding the Molarity Concept

Molarity (M) is a measure of the concentration of a solute in a solution. It is defined as the number of moles of solute divided by the volume of solution in liters (L). The formula for molarity is: \( M = \frac{\text{moles of solute}}{\text{volume of solution in liters}} \).
02

Calculating the Required Volume for 0.00100 mol Cl-

To find the volume needed to get 0.00100 mol of Cl-, use the molarity of the NaCl solution (0.150 M), which also represents the molarity of the Cl- ions since one mole of NaCl dissociates into one mole of Na+ and one mole of Cl-. Use the formula: \( V = \frac{\text{moles of solute}}{\text{Molarity}} \). For 0.00100 mol of Cl-, it will be: \( V = \frac{0.00100\,\text{mol}}{0.150\,\text{M}} = \frac{0.00100}{0.150} \) liters.
03

Calculating Mass for 0.00100 mol Cl-

Once the volume is calculated in liters, convert it to mass using the density of the solution. Assuming the density of the NaCl solution is the same as that of water (1 g/mL or 1 kg/L), we can convert directly from volume to mass. First calculate the volume in liters from the previous step, then multiply by 1000 to convert liters to milliliters (mL), and then use the density (1 g/mL) to find the mass in grams.
04

Repeat Steps 2 and 3 for 0.00500 mol Cl- and 0.0200 mol Cl-

The same calculations from steps 2 and 3 should be applied for calculating the volume and mass for 0.00500 mol Cl- and 0.0200 mol Cl-. You will use the molarity (0.150 M) and calculate the volume required for each amount of Cl-, then convert that volume to mass using the assumed density.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Molarity
Molarity is a crucial concept in chemistry, especially when mixing solutions for experiments or industry applications. It represents the concentration of a solute within a given volume of solution. The higher the molarity, the more solute is present per liter of solution. The molarity formula is
\( M = \frac{\text{moles of solute}}{\text{volume of solution in liters}} \).
Think of it like making lemonade; if you add more lemon juice (the solute) to the same amount of water, the lemonade becomes more concentrated or molar. To grasp this concept further, it's important to acknowledge that molarity calculations depend on the solute’s molar mass, the volume of the solution, and the desired concentration. Understanding molarity enables students to determine how much of a chemical to use to achieve a particular concentration, which is essential in performing accurate scientific experiments.
Concentration of Solutions
Concentration describes how much of a certain substance is mixed with another. In chemistry, concentration can refer to the amount of a substance in a particular volume of liquid. Imagine having a glass of water and steadily adding sugar; as more sugar is added, the mixture becomes sweeter and more concentrated. Similarly, molarity is one way to express the concentration of a solution quantitatively. It's valued for its precision in scientific contexts. When preparing solutions for various applications, it's necessary to achieve the exact concentration to ensure consistency and accuracy in research outcomes or products. If the concentration is off, it might lead to incorrect results or even dangerous reactions, which is why proper molarity calculations are foundational in the scientific field.
Moles of Solute
The term 'moles of solute' refers to the amount of a given substance present in a solution. A mole is a standard unit in chemistry that quantifies the amount of a substance based on the number of particles, like atoms or molecules, rather than its mass or volume. One mole is equivalent to Avogadro's number, which is approximately \(6.02 \times 10^{23}\) particles, matching the number of atoms in 12 grams of carbon-12.

For molarity calculations, knowing the moles of solute present is foundational. This is because molarity describes the moles of solute per liter of solution. To calculate moles, one can use the molar mass of the substance (found on the periodic table) and the mass of the solute used, reinforcing the interconnected nature of these concepts in stoichiometry and solution preparation.
Stoichiometry
Stoichiometry comes from a Greek term meaning 'measuring elements'. In chemistry, it involves calculations that relate the quantities of reactants and products in a chemical reaction. It applies the laws of conservation of mass and fixed composition, allowing chemists to predict the amounts of substances consumed and produced in a given reaction.

Stoichiometry also impacts molarity calculations. When you know the stoichiometry of a reaction, you can determine the amount of reactants needed to produce a desired amount of product, and vice versa. This allows for precise formulation of solutions. For instance, in the given exercise, the stoichiometry of sodium chloride (\(\mathrm{NaCl}\)) shows that one mole of \(\mathrm{NaCl}\) dissociates into one mole of sodium ions (\(\mathrm{Na}^{+}\)) and one mole of chloride ions (\(\mathrm{Cl}^{-}\)), enabling accurate calculations of the mass of \(\mathrm{NaCl}\) needed to get a required number of moles of chloride ions for various experiments.

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