How many atoms are in \(1.50 \mathrm{~mol}\) of carbon-12? How many grams does this much carbon-12 weigh?

Short Answer

Expert verified
There are 9.033 x 10^23 atoms in 1.50 mol of carbon-12. This amount of carbon-12 weighs 18 grams.

Step by step solution

01

Calculate the number of atoms in moles

To find the number of atoms in 1.50 mole of carbon-12, use Avogadro's number, which is 6.022 x 10^23 atoms per mole. Multiply the number of moles by Avogadro's number to get the total number of atoms.Number of atoms = Number of moles x Avogadro's numberNumber of atoms = 1.50 mol x (6.022 x 10^23 atoms/mol)
02

Calculate the mass of carbon-12 in grams

The molar mass of carbon-12 is exactly 12 grams per mole by definition. Multiply the number of moles by the molar mass to get the total mass in grams.Mass = Number of moles x Molar mass of carbon-12Mass = 1.50 mol x 12 g/mol

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Avogadro's Number
Imagine having a single cookie and wanting to know how many crumbs it could make. Avogadro’s number works similarly for atoms. It’s a constant that gives us the number of particles, usually atoms or molecules, in one mole of substance. This astounding number is approximately 6.022 x 10^23.
For our carbon-12 example, multiplying 1.50 moles by Avogadro's number gives us the total count of atoms. Just like knowing the crumb count tells us how many will scatter if the cookie crumbles, Avogadro's number lets us quantify the incredibly vast number of atoms in a substance with relative ease.
Molar Mass
Consider a classroom filled with different sets of building blocks. Molar mass can be equated to knowing the total weight of one set of blocks. It's the weight of one mole of a substance, usually expressed in grams per mole (g/mol).
For carbon-12, which is used as a standard, its molar mass is exactly 12 g/mol. So, if you have 1.50 moles of carbon-12, a simple multiplication operation gives you the mass in grams, much like estimating the collective weight of block sets in your classroom based on the weight of one.
Stoichiometry
In cooking, recipes tell us the amount of each ingredient needed for a dish. Stoichiometry is the 'recipe' of chemistry. It's a section of chemistry that deals with the relative quantities of reactants and products in chemical reactions.
In our example, stoichiometry assists in understanding how 1.50 moles of carbon-12 relate to other reactants or products in a reaction, like portions of ingredients translating to parts of a meal. Through stoichiometric calculations, chemists can precisely tweak amounts to obtain desired products, avoid waste, and maximize efficiency in reactions.
Atomic Mass Units
If we liken atoms to tiny fruits in a market, each having different sizes and masses, atomic mass units (amu) would be the scale that helps compare their weights. It is a standard unit of mass that quantifies how heavy an atom is, relative to one twelfth of a carbon-12 atom.
This unit gives us a way to discuss the incredibly minimal mass of atoms in terms we can comprehend. When talking about carbon-12, it has an atomic mass of exactly 12 amu, meaning it's used as a reference point for defining the atomic mass unit itself. Knowing the amu allows chemists and physicists to discuss and compare different atoms on a microscopic scale, facilitating deeper understanding and precise communication in the field of chemistry.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free