Write balanced molecular, ionic, and net ionic equations for the following pairs of reactants. If all ions cancel, indicate that no reaction (N.R.) takes place. (a) sodium sulfite and barium nitrate (b) formic acid \(\left(\mathrm{HCHO}_{2}\right)\) and potassium carbonate (c) ammonium bromide and lead(II) acetate (d) ammonium perchlorate and copper(II) nitrate

Short Answer

Expert verified
Part (a) - Net ionic: \(\text{SO}_3^{2-} + \text{Ba}^{2+} \rightarrow \text{BaSO}_3\). Part (b) - Net ionic: \(2\text{HCHO}_2 + \text{CO}_3^{2-} \rightarrow 2\text{HCHO}_2 + \text{H}_2\text{O} + \text{CO}_2\). Part (c) - Net ionic: \(2\text{Br}^- + \text{Pb}^{2+} \rightarrow \text{PbBr}_2\). Part (d) - No reaction.

Step by step solution

01

Part (a) - Molecular Equation

First, write the formulas for sodium sulfite (\(\text{Na}_2\text{SO}_3\)) and barium nitrate (\(\text{Ba}(\text{NO}_3)_2\)). Place them together as reactants and predict the products, which would be sodium nitrate (\(\text{NaNO}_3\)) and barium sulfite (\(\text{BaSO}_3\)). The molecular equation is: \(\text{Na}_2\text{SO}_3 + \text{Ba}(\text{NO}_3)_2 \rightarrow 2\text{NaNO}_3 + \text{BaSO}_3\).
02

Part (a) - Ionic Equations

Now, split the reactants and products into ions except for the precipitate, barium sulfite: \(2\text{Na}^+ + \text{SO}_3^{2-} + \text{Ba}^{2+} + 2\text{NO}_3^- \rightarrow 2\text{Na}^+ + 2\text{NO}_3^- + \text{BaSO}_3\).
03

Part (a) - Net Ionic Equation

Cancel the spectator ions to find the net ionic equation. Sodium and nitrate ions are spectators: \(\text{SO}_3^{2-} + \text{Ba}^{2+} \rightarrow \text{BaSO}_3\).
04

Part (b) - Molecular Equation

Write the formulas for formic acid (\(\text{HCHO}_2\)) and potassium carbonate (\(\text{K}_2\text{CO}_3\)). The products are potassium formate (\(\text{KCHO}_2\)) and carbonic acid which decomposes to water and carbon dioxide (\(\text{H}_2\text{O} + \text{CO}_2\)). The molecular equation is: \(2\text{HCHO}_2 + \text{K}_2\text{CO}_3 \rightarrow 2\text{KCHO}_2 + \text{H}_2\text{O} + \text{CO}_2\).
05

Part (b) - Ionic Equations

Formic acid is a weak acid and remains in molecular form, while potassium carbonate dissociates into ions: \(2\text{HCHO}_2 + 2\text{K}^+ + \text{CO}_3^{2-} \rightarrow 2\text{K}^+ + 2\text{HCHO}_2 + \text{H}_2\text{O} + \text{CO}_2\).
06

Part (b) - Net Ionic Equation

There's no change for potassium ions, so the net ionic equation focuses on the acid-base reaction: \(2\text{HCHO}_2 + \text{CO}_3^{2-} \rightarrow 2\text{HCHO}_2 + \text{H}_2\text{O} + \text{CO}_2\).
07

Part (c) - Molecular Equation

The formulas are ammonium bromide (\(\text{NH}_4\text{Br}\)) and lead(II) acetate (\(\text{Pb}(\text{C}_2\text{H}_3\text{O}_2)_2\)). The products are ammonium acetate (\(\text{NH}_4\text{C}_2\text{H}_3\text{O}_2\)) and lead(II) bromide (\(\text{PbBr}_2\)), which is a precipitate: \(2\text{NH}_4\text{Br} + \text{Pb}(\text{C}_2\text{H}_3\text{O}_2)_2 \rightarrow 2\text{NH}_4\text{C}_2\text{H}_3\text{O}_2 + \text{PbBr}_2\).
08

Part (c) - Ionic Equations

Decompose all the compounds except \(\text{PbBr}_2\) into ions: \(2\text{NH}_4^+ + 2\text{Br}^- + \text{Pb}^{2+} + 2\text{C}_2\text{H}_3\text{O}_2^- \rightarrow 2\text{NH}_4^+ + 2\text{C}_2\text{H}_3\text{O}_2^- + \text{PbBr}_2\).
09

Part (c) - Net Ionic Equation

Spectator ions (ammonium and acetate) are removed: \(2\text{Br}^- + \text{Pb}^{2+} \rightarrow \text{PbBr}_2\).
10

Part (d) - Molecular Equation

Write the formulas for ammonium perchlorate (\(\text{NH}_4\text{ClO}_4\)) and copper(II) nitrate (\(\text{Cu}(\text{NO}_3)_2\)). Since both products, ammonium nitrate (\(\text{NH}_4\text{NO}_3\)) and copper(II) perchlorate (\(\text{Cu}(\text{ClO}_4)_2\)), remain in solution and no precipitate forms, no reaction takes place. Indicate this by writing N.R.
11

Part (d) - Ionic and Net Ionic Equations

Since no reaction occurs, we cannot write ionic or net ionic equations for this part. Write N.R. for both.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Molecular Equations
A molecular equation provides a concise way of representing a chemical reaction by showing the chemical formulas of the reactants and products involved without expressing the ionic character of the compounds. Just as reading a recipe gives you an overview of the ingredients used without detailing how they're mixed, molecular equations reveal the reactants and products without delving into the ions that make them up.

For instance, when reacting sodium sulfite with barium nitrate, the molecular equation \(\text{Na}_2\text{SO}_3 + \text{Ba}(\text{NO}_3)_2 \rightarrow 2\text{NaNO}_3 + \text{BaSO}_3\) neatly presents the reactants and the products, bowing out of the specifics of how they interact ionically. In educational contexts, providing molecular equations is the first step towards an incremental exploration of reaction mechanics—setting the stage for deeper dives!
Ionic Equations
Think of ionic equations as the 'behind-the-scenes' footage of a play—the part where you get to see individual actors (ions) during a scene (reaction). In this representation, compounds that exist as ions in solution are shown as distinct cations and anions. It's a more detailed account compared to molecular equations because it acknowledges the actual form in which reactants exist in aqueous solutions.

For example, the ionic equation for the reaction between sodium sulfite and barium nitrate is articulated as \(2\text{Na}^+ + \text{SO}_3^{2-} + \text{Ba}^{2+} + 2\text{NO}_3^- \rightarrow 2\text{Na}^+ + 2\text{NO}_3^- + \text{BaSO}_3\), explicitly showing the dissociated ions from the soluble reactants and the net products. By doing so, ionic equations offer a clearer view of the action unfolding at the ion level, thus facilitating a more nuanced understanding of chemical processes.
Net Ionic Equations
Net ionic equations are the essence of a chemistry set, revealing the core reactions that define a given chemical interaction. By stripping away the spectator ions—those ions unchanged through the reaction process—only the ions that ultimately form the products are featured. It's akin to focusing on the pivotal players in a drama, disregarding the extras.

For the reaction between sodium sulfite and barium nitrate, the net ionic equation simplifies to \(\text{SO}_3^{2-} + \text{Ba}^{2+} \rightarrow \text{BaSO}_3\). It streamlines our understanding by concentrating on the formation of the insoluble precipitate, barium sulfite, sparing us the distraction of ancillary details. Grasping the concept of net ionic equations is crucial for students, as it highlights the fundamental processes at the heart of chemical reactions.
Precipitate Formation
In the grand dance of chemistry, precipitate formation is like the grand finale of a performance—it's the result that often indicates a successful reaction. A precipitate is a solid that emerges from solution as the product of a reaction between ions. It 'crashes' the solution party by becoming insoluble, so to speak.

The transition from soluble ions to an insoluble solid can be quite dramatic. For instance, when aqueous sodium sulfite meets barium nitrate, each soluble in their own right, they form barium sulfite, a solid that falls out of the solution. This tendency to precipitate is critical for many industrial processes and analytical techniques and can be predicted using solubility rules—an indispensable tool for any chemistry student.
Spectator Ions
There's a supporting cast in the theater of chemical reactions known as spectator ions. These ions maintain a presence from start to finish without actively participating in the reaction—they're present in both the reactants and products as dissolved ions and do not undergo any chemical change.

In the case of sodium sulfite and barium nitrate, the sodium \(\text{Na}^+\) and nitrate \(\text{NO}_3^-\) ions are the spectators. They're there for the ride without affecting the final outcome. Identifying these bystanders is an essential skill when crafting net ionic equations, helping to distill the reaction to its most essential parts.
Acid-Base Reactions
Acid-base reactions are like a formal dance between protons and hydroxide ions, a harmonious handover of hydrogen ions between acid and base. This specific type of chemical reaction is fundamental and drives processes ranging from digestion in our own bodies to industrial-scale manufacturing.

For instance, when formic acid reacts with potassium carbonate, it's an exchange—an acid-base tango that results in the formation of water and carbon dioxide. This neutralization process is emblematic of acid-base reactions and serves as an ideal playground for students to explore chemical principles of reactivity, stoichiometry, and conservation of mass. Through such reactions, students not only interpret the movement of protons but also come to appreciate the balance and elegance inherent in chemistry.

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