Use oxidation numbers to show that the fermentation of glucose, \(\mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{6},\) to carbon dioxide and ethanol, \(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH},\) is a redox reaction.

Short Answer

Expert verified
In the fermentation of glucose to ethanol and carbon dioxide, carbon atoms are oxidized to +4 in CO2 and reduced to -1 in ethanol, confirming it as a redox reaction.

Step by step solution

01

Write the balanced chemical equation for the fermentation of glucose

The chemical equation for the fermentation of glucose (C6H12O6) to produce ethanol (C2H5OH) and carbon dioxide (CO2) is written as: C6H12O6 -> 2 C2H5OH + 2 CO2. Ensure the equation is balanced with respect to atoms of each element and charge.
02

Assign oxidation numbers to carbon in the reactants and products

Assign oxidation numbers to the carbon atoms in glucose, ethanol, and carbon dioxide. In Glucose, all carbon atoms have an oxidation number of 0, because it’s a pure element. In Ethanol, the carbon of the -CH3 group is -3, and the carbon of the -CH2OH group is -1. In CO2, each carbon has an oxidation number of +4.
03

Identify the changes in oxidation numbers

Compare the oxidation numbers of carbon in the reactants and products. In the reaction, we find that carbon in glucose goes from an oxidation number of 0 to +4 in CO2, showing an increase in the oxidation number which indicates oxidation. At least one carbon in glucose goes from an oxidation number of 0 to -1 in ethanol, showing a decrease in the oxidation number which indicates reduction.
04

Conclude that the fermentation is a redox reaction

Since the process involves both oxidation (loss of electrons) and reduction (gain of electrons) as evidenced by the changes in oxidation numbers for the carbon atoms, it can be concluded that the fermentation of glucose to produce ethanol and carbon dioxide is indeed a redox reaction.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Oxidation Numbers
Understanding oxidation numbers is crucial for identifying redox reactions. An oxidation number is a figure assigned to an element in a chemical species that represents the number of electrons lost or shared as compared to its elemental state. In simple terms, it's like a bookkeeping system to track electrons during a chemical reaction.

For example, in a molecule of glucose, \( \mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{6} \), the oxidation number for each carbon atom is 0, because this is the standard for elements in their basic, uncombined form. When analyzing the products of glucose fermentation, such as ethanol, \( \mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH} \) and carbon dioxide (CO2), different oxidation numbers are necessary. In ethanol, the carbon atoms have differing oxidation states because of the distinct nature of their bonds. In carbon dioxide, each carbon atom is assigned an oxidation number of +4 due to the nature of its double bonds with oxygen.

Recognizing these changes in oxidation numbers helps indicate what is losing electrons (oxidation) and what is gaining electrons (reduction) during the reaction.
Redox Reaction
A redox reaction is characterized by the transfer of electrons between chemical species, resulting in changes in their oxidation states. This transfer leads to one species being oxidized (losing electrons) and another being reduced (gaining electrons). Understanding a redox reaction is essential for delving into the chemistry behind processes like the fermentation of glucose.

Fermentation is an anaerobic process, meaning it occurs without oxygen. During the conversion of glucose into ethanol and carbon dioxide, electrons are redistributed among the carbon atoms, changing their oxidation numbers. The shift in electrons confirms that a redox reaction is taking place, with certain carbon atoms being oxidized, while others are reduced.
Chemical Equation Balancing
The process of chemical equation balancing involves ensuring that the number of atoms for each element, and the total charge, are the same on both the reactant and product sides. This law of conservation of mass is paramount because, in a chemical reaction, matter is neither created nor destroyed.

For example, in the fermentation of glucose, the balanced chemical equation is \( \mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{6} \rightarrow 2 \mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH} + 2 \mathrm{CO}_{2} \). This balance reflects that there are six carbon atoms, twelve hydrogen atoms, and six oxygen atoms on both sides of the equation, demonstrating that mass is conserved through the reaction.
Oxidation and Reduction
Oxidation and reduction are two halves of a redox reaction. Often remembered by the mnemonic 'OIL RIG'—which stands for 'Oxidation Is Loss, Reduction Is Gain'—these processes refer to the loss and gain of electrons, respectively.

In the context of glucose fermentation, oxidation involves glucose's carbon atoms increasing their oxidation number, as seen by the carbon going from 0 in glucose to +4 in carbon dioxide. This increase indicates a loss of electrons. Conversely, reduction involves the decrease in the oxidation number—like the carbon atoms in glucose that end up in ethanol, moving from 0 to -1. This is a clear sign of a gain of electrons. The simultaneous occurrence of these two processes is what makes a reaction redox.

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Most popular questions from this chapter

One pollutant in smog is nitrogen dioxide, \(\mathrm{NO}_{2}\). The gas has a reddish brown color and is responsible for the redbrown color associated with this type of air pollution. \(\mathrm{Ni}\) trogen dioxide is also a contributor to acid rain because when rain passes through air contaminated with \(\mathrm{NO}_{2}\), it dissolves and undergoes the following reaction: \(\mathrm3{NO}_{2}(g)+\mathrm{H}_{2} \mathrm{O} \longrightarrow \mathrm{NO}(g)+2 \mathrm{H}^{+}(a q)+2 \mathrm{NO}_{3}^{-}(a q)\) In this reaction, which element is reduced and which is oxidized? Which is the oxidizing agent and which is the reducing agent?

Assign oxidation numbers to the elements in the and following: (a) \(\mathrm{MnCl}_{2}\), (b) \(\mathrm{MnO}_{4}^{-}\) (c) \(\mathrm{MnO}_{4}^{2-},\) (d) \(\mathrm{MnO}_{2}\)

When balancing redox reactions, which side of a halfreaction gets the electrons?

Balance the following equations for reactions occurring in an acidic solution. (a) \(\mathrm{NO}_{3}^{-}+\mathrm{Zn} \longrightarrow \mathrm{NH}_{4}^{+}+\mathrm{Zn}^{2+}\) (b) \(\mathrm{Cr}^{3+}+\mathrm{BiO}_{3}^{-} \longrightarrow \mathrm{Cr}_{2} \mathrm{O}_{7}^{2-}+\mathrm{Bi}^{3+}\) (c) \(\mathrm{I}_{2}+\mathrm{OCl}^{-} \longrightarrow \mathrm{IO}_{3}^{-}+\mathrm{Cl}^{-}\) (d) \(\mathrm{Mn}^{2+}+\mathrm{BiO}_{3}^{-} \longrightarrow \mathrm{MnO}_{4}^{-}+\mathrm{Bi}^{3+}\)

Both calcium chloride and sodium chloride are used to melt ice and snow on roads in the winter. A certain company was marketing a mixture of these two compounds for this purpose. A chemist, wanting to analyze the mixture, dissolved \(2.463 \mathrm{~g}\) of it in water and precipitated calcium oxalate by adding sodium oxalate, \(\mathrm{Na}_{2} \mathrm{C}_{2} \mathrm{O}_{4}\) The calcium oxalate was carefully filtered from the solution, dissolved in sulfuric acid, and titrated with 0.1000 \(M \mathrm{KMnO}_{4}\) solution. The reaction that occurred was \(6 \mathrm{H}^{+}+5 \mathrm{H}_{2} \mathrm{C}_{2} \mathrm{O}_{4}+2 \mathrm{MnO}_{4}^{-} \longrightarrow\) $$ 10 \mathrm{CO}_{2}+2 \mathrm{Mn}^{2+}+8 \mathrm{H}_{2} \mathrm{O} $$ The titration required \(21.62 \mathrm{~mL}\) of the \(\mathrm{KMnO}_{4}\) solution. (a) How many moles of \(\mathrm{C}_{2} \mathrm{O}_{4}^{2-}\) were present in the calcium oxalate precipitate? (b) How many grams of calcium chloride were in the original \(2.463 \mathrm{~g}\) sample? (c) What was the percentage by mass of calcium chloride in the sample?

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