What fundamental fact about \(\Delta H\) makes Hess's law possible?

Short Answer

Expert verified
\(\Delta H\) is a state function; this means it is path-independent and relies only on the initial and final states, which makes Hess's law possible.

Step by step solution

01

Understanding Hess's Law

Hess's law states that the total enthalpy change for a reaction is the same, regardless of the number of steps the reaction is carried out in. This is due to the fact that enthalpy is a state function.
02

Identifying the Fundamental Fact

The fundamental fact about \(\Delta H\) is that it is a state function. A state function is a property of a system that depends only on the current state of the system, not on the path or manner in which that state was achieved.
03

Understanding State Functions

Because enthalpy is a state function, the change in enthalpy (\(\Delta H\)) for a reaction depends only on the initial and final states of the system and not on the path taken. Therefore, multiple steps leading to the final reaction amount to the same enthalpy change as a direct one-step reaction.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Enthalpy Change
When we talk about enthalpy change, denoted as \( \Delta H \), we refer to the difference in the total heat content of a system between the initial and final state of a chemical process at constant pressure. It's an essential concept within chemical reactions, as it helps us understand the energy flow during these processes. The enthalpy change can be either endothermic or exothermic; where endothermic reactions absorb heat \( \Delta H > 0 \) and exothermic reactions release heat \( \Delta H < 0 \).

Consider a simple chemical reaction where reactants transform into products. Even if this reaction occurs in a single step or multiple stages, the total enthalpy change remains the same. This consistency lies at the heart of Hess's Law which means that if you were to diagram a reaction pathway showing potential energy along the y-axis and reaction progress along the x-axis, the overall 'height' difference between reactants and products tells you the enthalpy change—and this doesn't alter regardless of the route taken.
State Function
A state function is a property that's determined by the current condition of the system, such as pressure, temperature, volume, and, notably, enthalpy. It is independent of the path used to reach that state. Imagine hiking to a mountain's summit; no matter which trail you take, the elevation at the top is the same. That elevation is akin to a state function - it only depends on the final and initial points, not on the path you took to get there.

Why Enthalpy is a State Function

Consider a beaker of water at a certain temperature and pressure. If we were to measure the enthalpy of the water, it wouldn't matter if the water was heated directly to that temperature, or if it was first frozen and then melted back. The enthalpy value would remain the same because it is a state function; dependent only on the water's present temperature and pressure, not on how it arrived there.
Chemical Thermodynamics
At its core, chemical thermodynamics deals with the energy transformations in chemical reactions and the laws that govern these transformations. It's a bridge between the microscopic properties of molecules and the macroscopic properties of materials that we can observe and measure.

In chemical thermodynamics, Hess's Law is a fundamental principle. It provides a powerful tool for predicting the enthalpy changes of reactions by allowing us to combine known enthalpies from related reactions. This law applies the notion that energy is conserved in a closed system. Hence, despite the complexity of pathways in a reaction, the energy change remains constant if the initial and final conditions are unchanged. It means thermodynamics gives us the foresight to understand energy changes in reactions without needing to physically conduct the reaction step-by-step—an incredible advantage for predicting the feasibility and spontaneity of chemical processes.

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Most popular questions from this chapter

A \(1.000 \mathrm{~mol}\) sample of propane, a gas used for cooking in many rural areas, was placed in a bomb calorimeter with excess oxygen and ignited. The initial temperature of the calorimeter was \(25.000^{\circ} \mathrm{C}\) and its total heat capacity was \(97.13 \mathrm{~kJ}^{\circ} \mathrm{C}^{-1}\). The reaction raised the temperature of the calorimeter to \(27.282^{\circ} \mathrm{C}\). (a) Write the balanced chemical equation for the reaction in the calorimeter. (b) How many joules were liberated in this reaction? (c) What is the heat of reaction of propane with oxygen expressed in kilojoules per mole of \(\mathrm{C}_{3} \mathrm{H}_{8}\) burned?

A vat of \(4.54 \mathrm{~kg}\) of water underwent a decrease in temperature from \(60.25^{\circ} \mathrm{C}\) to \(58.65^{\circ} \mathrm{C}\). How much energy in kilojoules left the water? (For this range of temperature, use a value of \(4.18 \mathrm{~J} \mathrm{~g}^{-1}{ }^{\circ} \mathrm{C}^{-1}\) for the specific heat of water.

What is meant by the term chemical energy?

If the mass of a truck is doubled - for example, when it is loaded - by what factor does the kinetic energy of the truck increase? By what factor does the kinetic energy change if the mass is one-tenth of the original mass?

Given the following thermochemical equations, $$ 3 \mathrm{Mg}(s)+2 \mathrm{NH}_{3}(g) \longrightarrow \mathrm{Mg}_{3} \mathrm{~N}_{2}(s)+3 \mathrm{H}_{2}(g) $$ \(\Delta H^{\circ}=-371 \mathrm{~kJ}\) $$ \frac{1}{2} \mathrm{~N}_{2}(g)+\frac{3}{2} \mathrm{H}_{2}(g) \longrightarrow \mathrm{NH}_{3}(g) \quad \Delta H^{\circ}=-46 \mathrm{~kJ} $$ calculate \(\Delta H^{\circ}\) (in kilojoules) for the following reaction: $$ 3 \mathrm{Mg}(s)+\mathrm{N}_{2}(g) \longrightarrow \mathrm{Mg}_{3} \mathrm{~N}_{2}(s) $$

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