Chapter 6: Problem 44
What fundamental fact about \(\Delta H\) makes Hess's law possible?
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Chapter 6: Problem 44
What fundamental fact about \(\Delta H\) makes Hess's law possible?
These are the key concepts you need to understand to accurately answer the question.
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Get started for freeA \(1.000 \mathrm{~mol}\) sample of propane, a gas used for cooking in many rural areas, was placed in a bomb calorimeter with excess oxygen and ignited. The initial temperature of the calorimeter was \(25.000^{\circ} \mathrm{C}\) and its total heat capacity was \(97.13 \mathrm{~kJ}^{\circ} \mathrm{C}^{-1}\). The reaction raised the temperature of the calorimeter to \(27.282^{\circ} \mathrm{C}\). (a) Write the balanced chemical equation for the reaction in the calorimeter. (b) How many joules were liberated in this reaction? (c) What is the heat of reaction of propane with oxygen expressed in kilojoules per mole of \(\mathrm{C}_{3} \mathrm{H}_{8}\) burned?
A vat of \(4.54 \mathrm{~kg}\) of water underwent a decrease in temperature from \(60.25^{\circ} \mathrm{C}\) to \(58.65^{\circ} \mathrm{C}\). How much energy in kilojoules left the water? (For this range of temperature, use a value of \(4.18 \mathrm{~J} \mathrm{~g}^{-1}{ }^{\circ} \mathrm{C}^{-1}\) for the specific heat of water.
What is meant by the term chemical energy?
If the mass of a truck is doubled - for example, when it is loaded - by what factor does the kinetic energy of the truck increase? By what factor does the kinetic energy change if the mass is one-tenth of the original mass?
Given the following thermochemical equations, $$ 3 \mathrm{Mg}(s)+2 \mathrm{NH}_{3}(g) \longrightarrow \mathrm{Mg}_{3} \mathrm{~N}_{2}(s)+3 \mathrm{H}_{2}(g) $$ \(\Delta H^{\circ}=-371 \mathrm{~kJ}\) $$ \frac{1}{2} \mathrm{~N}_{2}(g)+\frac{3}{2} \mathrm{H}_{2}(g) \longrightarrow \mathrm{NH}_{3}(g) \quad \Delta H^{\circ}=-46 \mathrm{~kJ} $$ calculate \(\Delta H^{\circ}\) (in kilojoules) for the following reaction: $$ 3 \mathrm{Mg}(s)+\mathrm{N}_{2}(g) \longrightarrow \mathrm{Mg}_{3} \mathrm{~N}_{2}(s) $$
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