Chapter 9: Problem 126
Cyclopropane is a triangular molecule with \(\mathrm{C}-\mathrm{C}-\mathrm{C}\) bond angles of \(60^{\circ} .\) Explain why the \(\sigma\) bonds joining carbon atoms in cyclopropane are weaker than the carboncarbon \(\sigma\) bonds in the noncyclic propane.
Short Answer
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.