Predict the shapes of (a) \(\mathrm{NH}_{2}^{-}\), (b) \(\mathrm{CO}_{3}^{2-}\), (c) \(\mathrm{IF}_{3},\) (d) \(\mathrm{Br}_{3}^{-},\) and (e) \(\mathrm{GaH}_{3}\).

Short Answer

Expert verified
The molecular geometries are (a) bent or V-shaped for \(\mathrm{NH}_{2}^{-}\), (b) trigonal planar for \(\mathrm{CO}_{3}^{2-}\), (c) T-shaped for \(\mathrm{IF}_{3}\), (d) trigonal pyramidal for \(\mathrm{Br}_{3}^{-}\), and (e) trigonal planar for \(\mathrm{GaH}_{3}\).

Step by step solution

01

Determine the Electron Geometry of \(\mathrm{NH}_{2}^{-}\)

The molecule \(\mathrm{NH}_{2}^{-}\) has a nitrogen atom with 5 valence electrons plus 1 extra electron due to the negative charge, and 2 hydrogen atoms each with 1 valence electron. This sums up to 8 electrons, which means the nitrogen atom has 4 electron pairs (2 bonding pairs and 2 lone pairs). According to the VSEPR theory, 4 electron pairs result in a tetrahedral electron geometry. However, because the molecule has 2 lone pairs, the molecular geometry will be bent or V-shaped.
02

Determine the Molecular Geometry of \(\mathrm{CO}_{3}^{2-}\)

In the carbonate ion, \(\mathrm{CO}_{3}^{2-}\), carbon is the central atom with 4 valence electrons, and each oxygen has 6 valence electrons, summing to 18 valence electrons plus 2 extra electrons for the charge, giving a total of 20 valence electrons. This means there are 3 bonding pairs and 2 lone pairs on the oxygen atoms, but none on the central carbon. The electron geometry is trigonal planar, and since all pairs are bonding pairs, the molecular geometry is also trigonal planar.
03

Determine the Electron Geometry of \(\mathrm{IF}_{3}\)

Iodine in \(\mathrm{IF}_{3}\) has 7 valence electrons, with 3 fluorine atoms each contributing 1 electron, accounting for 3 valence electrons. There are a total of 10 electrons or 5 electron pairs around the central iodine atom. These 5 electron pairs arrange themselves in a trigonal bipyramid electron geometry. However, with 2 lone pairs on iodine, the molecular shape becomes T-shaped.
04

Determine the Molecular Geometry of \(\mathrm{Br}_{3}^{-}\)

For the \(\mathrm{Br}_{3}^{-}\) ion, each bromine atom contributes 7 valence electrons, and the extra electron from the charge makes it 22 in total. Thus, there are 4 electron pairs (3 bonding pairs and 1 lone pair) around the central bromine atom, which initially corresponds to a tetrahedral electron geometry. With one lone pair, the molecular geometry becomes trigonal pyramidal.
05

Determine the Molecular Geometry of \(\mathrm{GaH}_{3}\)

Gallium in \(\mathrm{GaH}_{3}\) has 3 valence electrons, and each hydrogen has 1 electron, totaling 3 bonding pairs of electrons with no lone pairs around the central gallium atom. The electron pairs are arranged in a trigonal planar electron geometry, and the molecular geometry is the same due to the absence of lone pairs.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding VSEPR Theory
The Valence Shell Electron Pair Repulsion (VSEPR) theory is fundamental for predicting the shape of molecules. At its core, VSEPR theory states that electron pairs surrounding an atom naturally repel each other, and they will arrange themselves as far apart as possible to minimize this repulsion. This behavior is due to the negative charge of the electrons which causes them to repel one another.

When we look at a molecule's structure, we focus primarily on the valence electrons of the central atom. These electrons, which may exist in pairs, dictate the spatial arrangement of the atoms within the molecule. For example, in the case of \(\mathrm{NH}_{2}^{-}\), the central nitrogen atom has four electron pairs that determine the molecular geometry.
Electron Pair Arrangement
The arrangement of electron pairs is significantly influenced by the number of pairs around a central atom. When we talk about electron pairs, we refer to both bonding pairs (electron pairs shared with other atoms to form bonds) and lone pairs (non-bonded electron pairs) around the central atom. The electron geometry is the three-dimensional arrangement of these electron pairs, which may be tetrahedral, trigonal planar, linear, octahedral, or various other configurations depending on the count and nature of electron pairs.

For instance, the carbonate ion \(\mathrm{CO}_{3}^{2-}\) exhibits a trigonal planar electron geometry because all its electron pairs are involved in bonding with no lone pairs on the central carbon atom.
The Role of Lone Pairs and Bonding Pairs
A pivotal distinction in molecular geometry comes from understanding the difference between lone pairs and bonding pairs of electrons. Bonding pairs are shared between atoms, forming covalent bonds that create the skeleton of a molecule. In contrast, lone pairs are not shared and typically occupy more space than bonding pairs, leading to distortions in the geometry of a molecule.

For example, in the molecule iodine trifluoride \(\mathrm{IF}_{3}\), the presence of two lone pairs on the iodine atom causes a deviation from the expected trigonal bipyramidal electron geometry to a T-shaped molecular shape. This alteration is due to the extra space that lone pairs require.
Predicting Molecular Shapes
The shape of a molecule is different from the electron geometry and is described as the molecular geometry. It factors in only the positions of the atomic nuclei, considering the spatial arrangements of atoms linked by chemical bonds regardless of the electron pair arrangement. This means that while the electron pair geometry considers both bonding and lone pairs, molecular shape reflects only the arrangement of atoms.

In the molecule gallium trihydride \(\mathrm{GaH}_{3}\), for instance, despite the electron pair geometry being trigonal planar, it's the same as the molecular shape since there are no lone pairs to alter the arrangement.

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