The average radius of a molecule of lysozyme, an enzyme in tears, is \(1430 \mathrm{pm}\). What is its radius in nanometers (nm)?

Short Answer

Expert verified
1.43 nm

Step by step solution

01

Understand the units

The given radius is in picometers (pm), and we need to convert it to nanometers (nm). Recall that 1 nanometer (nm) is equal to 1000 picometers (pm).
02

Set up the conversion factor

Since 1 nm is equal to 1000 pm, we can write the conversion factor as \[ 1 \text{ nm} = 1000 \text{ pm} \].
03

Convert the radius

Divide the given value in picometers (pm) by the conversion factor to get the value in nanometers (nm). \[ \text{Radius in nm} = 1430 \text{ pm} \times \frac{1 \text{ nm}}{1000 \text{ pm}} \]
04

Perform the calculation

Do the division: \[ 1430 \text{ pm} \times \frac{1 \text{ nm}}{1000 \text{ pm}} = 1.43 \text{ nm} \].
05

Write the final answer

The radius of a molecule of lysozyme is 1.43 nanometers (nm).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

picometers to nanometers conversion
To convert picometers to nanometers, we need to understand the relationship between these units. A picometer (pm) is one of the smallest units of length and is equal to one trillionth of a meter, while a nanometer (nm) is one billionth of a meter.

Recall that 1 nanometer (nm) represents 1000 picometers (pm). Knowing this, we can easily convert any value in picometers to nanometers by dividing by 1000.

For example, to convert 1430 pm to nm:
  • Set up the conversion factor: \[ 1 \text{ nm} = 1000 \text{ pm} \]

  • Divide the number of picometers by 1000: \[ 1430 \text{ pm} \times \frac{1 \text{ nm}}{1000 \text{ pm}} = 1.43 \text{ nm} \]

This gives us the equivalent value in nanometers, which is the necessary conversion for various scientific measurements.
lysozyme molecular radius
Lysozyme is an enzyme found in many bodily fluids like tears and saliva. It plays a crucial role in preventing bacterial infections by breaking down the cell walls of bacteria—essentially acting as part of the body's immune defense.

The average radius of a lysozyme molecule is 1430 picometers (pm). To have a better understanding of its size at a more manageable scale, we convert this radius to nanometers (nm).

Using the previous conversion, we find that the radius is 1.43 nm:
  • Initial radius: 1430 pm
  • Convert using factor: \[ 1430 \text{ pm} \times \frac{1 \text{ nm}}{1000 \text{ pm}} = 1.43 \text{ nm} \]

This size is incredibly small, showcasing the molecular scale at which lysozymes operate to protect us. This tiny radius gives insight into the efficiency and effectiveness of lysozymes in fighting off bacterial invaders.
basic chemistry calculations
Basic chemistry calculations often involve unit conversions, as we saw with converting picometers to nanometers. These conversions are critical for understanding and working with different chemical substances and their properties.

Here are a few tips for handling these kinds of calculations:
  • Always identify the units you are starting with and the units you need to convert to. This sets a clear goal for your calculation.

  • Use correct conversion factors. Make sure to know the relationship between the units correctly, such as 1 nm = 1000 pm.

  • Set up the conversion factor as a fraction to help you easily cancel out the units and perform the calculation. In the case of picometers to nanometers: \[ 1430 \text{ pm} \times \frac{1 \text{ nm}}{1000 \text{ pm}} = 1.43 \text{ nm} \]

  • Double-check your calculations to avoid errors. Simple mistakes can lead to incorrect answers.

By practicing these strategies, basic chemistry calculations can become straightforward and manageable, allowing for a deeper understanding of the material.

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Most popular questions from this chapter

Bromine is used to prepare the pesticide methyl bromide and flame retardants for plastic electronic housings. It is recovered from seawater, underground brines, and the Dead Sea. The average concentrations of bromine in seawater \((d=1.024 \mathrm{~g} / \mathrm{mL})\) and the Dead Sea \((d=1.22 \mathrm{~g} / \mathrm{mL})\) are \(0.065 \mathrm{~g} / \mathrm{L}\) and \(0.50 \mathrm{~g} / \mathrm{L},\) respectively. What is the mass ratio of bromine in the Dead Sea to that in seawater?

Carry out the following calculations, making sure that your answer has the correct number of significant figures: (a) \(\frac{2.420 \mathrm{~g}+15.6 \mathrm{~g}}{4.8 \mathrm{~g}}\) (b) \(\frac{7.87 \mathrm{~mL}}{16.1 \mathrm{~mL}-8.44 \mathrm{~mL}}\) (c) \(V=\pi r^{2} h,\) where \(r=6.23 \mathrm{~cm}\) and \(h=4.630 \mathrm{~cm}\)

Carry out each calculation, paying special attention to significant figures, rounding, and units \((J=\) joule, the \(S I\) unit of encrgy; mol = mole, the SI unit for amount of substance): (a) \(\frac{\left(6.626 \times 10^{-34} \mathrm{~J} \cdot \mathrm{s}\right)\left(2.9979 \times 10^{8} \mathrm{~m} / \mathrm{s}\right)}{489 \times 10^{-9} \mathrm{~m}}\) (b) \(\frac{\left(6.022 \times 10^{23} \text { molecules } / \mathrm{mol}\right)\left(1.23 \times 10^{2} \mathrm{~g}\right)}{46.07 \mathrm{~g} / \mathrm{mol}}\) (c) \(\left(6.022 \times 10^{23}\right.\) atoms \(\left./ \mathrm{mol}\right)\left(1.28 \times 10^{-18} \mathrm{~J} /\right.\) atom \()\left(\frac{1}{2^{2}}-\frac{1}{3^{2}}\right)\) where the numbers 2 and 3 in the last term are exact

Why is a quantitative observation more useful than a nonquantitative one? Which of the following is (are) quantitative? (a) The Sun rises in the east. (b) A person weighs one-sixth as much on the Moon as on Earth. (c) Ice floats on water. (d) A hand pump cannot draw water from a well more than \(34 \mathrm{ft}\) deep.

Carry out each calculation, paying special attention to significant figures, rounding, and units: (a) \(\frac{4.32 \times 10^{7} \mathrm{~g}}{\frac{4}{3}(3.1416)\left(1.95 \times 10^{2} \mathrm{~cm}\right)^{3}}\) (The term \(\frac{4}{3}\) is exact.) (b) \(\frac{\left(1.84 \times 10^{2} \mathrm{~g}\right)(44.7 \mathrm{~m} / \mathrm{s})^{2}}{2}\) (The term 2 is exact.) (c) \(\frac{\left(1.07 \times 10^{-4} \mathrm{~mol} / \mathrm{L}\right)^{2}\left(3.8 \times 10^{-3} \mathrm{~mol} / \mathrm{L}\right)}{\left(8.35 \times 10^{-5} \mathrm{~mol} / \mathrm{L}\right)\left(1.48 \times 10^{-2} \mathrm{~mol} / \mathrm{L}\right)^{3}}\)

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