Write a balanced equation for each reaction: (a) "Slaking" of lime (treatment with water) (b) Combustion of calcium in air

Short Answer

Expert verified
(a) CaO + H2O → Ca(OH)2 (b) 2 Ca + O2 → 2 CaO

Step by step solution

01

Title - Understanding Slaking of Lime

Slaking of lime involves treating calcium oxide (CaO) with water (H2O) to form calcium hydroxide (Ca(OH)2).
02

Title - Writing the Unbalanced Equation for Slaking

Write the unbalanced equation for the reaction: CaO + H2O → Ca(OH)2.
03

Title - Balancing the Equation for Slaking

Check the number of atoms on both sides. Here, one calcium, one oxygen, and two hydrogen atoms exist on both sides of the equation already. Therefore, it is balanced: CaO + H2O → Ca(OH)2.
04

Title - Understanding Combustion of Calcium

Combustion of calcium in air involves reacting calcium (Ca) with oxygen (O2) to form calcium oxide (CaO).
05

Title - Writing the Unbalanced Equation for Combustion

Write the unbalanced equation for the reaction: Ca + O2 → CaO.
06

Title - Balancing the Equation for Combustion

Check the number of atoms on both sides. Since one molecule of O2 provides two oxygen atoms:1. Balance oxygen by ensuring there are two CaO molecules. Equation becomes: 2 Ca + O2 → 2 CaO.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Slaking of Lime
Slaking of lime is a common process in construction and industrial applications. It involves the reaction between calcium oxide (also known as quicklime) and water to produce calcium hydroxide, commonly referred to as slaked lime.

Calcium oxide (CaO) is a white, caustic, alkaline substance derived from the thermal decomposition of limestone. When water is added to calcium oxide, a highly exothermic reaction occurs, releasing a significant amount of heat and forming calcium hydroxide \text{Ca(OH)}_{2}.

This reaction can be represented as:
\[ \text{CaO} + \text{H}_2\text{O} \rightarrow \text{Ca(OH)}_2 \]

To ensure that the chemical equation is balanced, we compare the number of each type of atom on both sides of the equation. In this case:
  • 1 calcium atom on both sides
  • 2 hydrogen atoms on both sides
  • 2 oxygen atoms on both sides
The balanced equation is:
\[ \text{CaO} + \text{H}_2\text{O} \rightarrow \text{Ca(OH)}_2 \]

Slaked lime has various uses, such as in mortar for building construction, in water treatment to soften water, and in agriculture to neutralize acidic soils.
Combustion Reaction
Combustion reactions are types of chemical reactions where a substance combines with oxygen, releasing energy in the form of light and heat. In the case of calcium, combustion involves the reaction of calcium metal with oxygen from the air.

Initially, the unbalanced equation for the combustion of calcium can be written as:
\[ \text{Ca} + \text{O}_2 \rightarrow \text{CaO} \]

To balance this equation, we need to ensure that the number of atoms of each element is the same on both sides. Since \text{O}_2 provides two oxygen atoms, we need two calcium oxide (CaO) molecules to balance the oxygen atoms. This gives the balanced equation:
\[ 2 \text{Ca} + \text{O}_2 \rightarrow 2 \text{CaO} \]

This means that two moles of calcium react with one mole of oxygen to yield two moles of calcium oxide. Combustion of calcium is a highly exothermic reaction, meaning it releases a lot of heat and can produce a bright white light. It’s a good example of a metal reacting with oxygen to form an oxide.
Calcium Reactions
Calcium is an alkaline earth metal, commonly found in compounds like limestone (\text{CaCO}_3). It readily reacts with various substances, resulting in important industrial and biological compounds.

Here are some notable reactions involving calcium:
  • With water: Calcium reacts slowly with cold water to form calcium hydroxide and hydrogen gas. This reaction is less vigorous compared to its reaction with acids:
    \[ \text{Ca} + 2 \text{H}_2\text{O} \rightarrow \text{Ca(OH)}_2 + \text{H}_2 \]
  • With acids: Calcium reacts with acids to produce a salt and release hydrogen gas. For example, with hydrochloric acid (HCl), the reaction is:
    \[ \text{Ca} + 2 \text{HCl} \rightarrow \text{CaCl}_2 + \text{H}_2 \]
  • With oxygen: As covered in the combustion reaction, calcium reacts with oxygen to form calcium oxide.
Calcium compounds, such as calcium carbonate (\text{CaCO}_3), calcium sulfate (\text{CaSO}_4), and calcium phosphate (\text{Ca}_3(\text{PO}_4)_2), play crucial roles in various fields. For example, \text{CaCO}_3 is a primary component of cement and lime, used widely in construction, while calcium ions are essential in biological systems, especially for bone health and cellular functions.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Indium (In) reacts with \(\mathrm{HCl}\) to form a diamagnetic solid with the formula \(\ln \mathrm{Cl}_{2}\). (a) Write condensed electron configurations for \(\mathrm{In}, \mathrm{In}^{+}, \mathrm{In}^{2+}\) and \(\mathrm{In}^{3+}\) (b) Which of these species is (are) diamagnetic and which paramagnetic? (c) What is the apparent oxidation state of In in \(\mathrm{InCl}_{2}\) ? (d) Given your answers to parts (b) and (c), explain how \(\mathrm{InCl}_{2}\) can be diamagnetic.

Explain why Xe, and to a limited extent \(\mathrm{Kr},\) form compounds, whereas He, Ne, and Ar do not.

Which group(s) of the periodic table is (are) described by each of the following general statements? (a) The elements form compounds of VSEPR class \(A X_{3} E\). (b) The free elements are strong oxidizing agents and form monatomic ions and oxoanions. (c) The atoms form compounds by combining with two other atoms that donate one electron each. (d) The free elements are strong reducing agents, show only one nonzero oxidation state, and form mainly ionic compounds. (c) The elements can form stable compounds with only three bonds, but, as a central atom, they can accept a pair of electrons from a fourth atom without expanding their valence shell. (f) Only larger members of the group are chemically active.

Complete and balance the following: (a) \(\mathrm{NaHSO}_{4}(a q)+\mathrm{NaOH}(a q) \longrightarrow\) (b) \(\mathrm{S}_{8}(s)+\operatorname{excess} \mathrm{F}_{2}(g) \longrightarrow\) (c) \(\mathrm{FeS}(s)+\mathrm{HCl}(a q) \longrightarrow\) (d) \(\mathrm{Te}(s)+\mathrm{I}_{2}(s) \longrightarrow\)

Complete and balance the following: (a) \(\mathrm{H}_{2} \mathrm{~S}(g)+\mathrm{O}_{2}(g) \longrightarrow\) (b) \(\mathrm{SO}_{3}(g)+\mathrm{H}_{2} \mathrm{O}(l) \longrightarrow\) (c) \(\mathrm{SF}_{4}(g)+\mathrm{H}_{2} \mathrm{O}(I) \longrightarrow\) (d) \(\mathrm{Al}_{2} \mathrm{Se}_{3}(s)+\mathrm{H}_{2} \mathrm{O}(l) \longrightarrow\)

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free